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eduard
3 years ago
11

What is the molarity (M) of a solution with 2 mol of NaCl in 0.50 L of solution?

Chemistry
1 answer:
irinina [24]3 years ago
5 0

Answer:

The answer to your question is 4 M

Explanation:

Data

NaCl 2 moles

Volume = 0.5 l

Molarity = M

Process

1.- Write the formula of Molarity

     Molarity = \frac{number of moles}{volume (liters)}

2.- Substitution

     Molarity = \frac{2 moles}{0.5 liters}

3.- Simplification and result

             Molarity = 4 M

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what is the limiting reactant when 1.50g of lithium and 1.50 g of nitrogen combine to form lithium nitride, a component of advan
PSYCHO15rus [73]
<h3>Answer:</h3>

Limiting reactant is Lithium

<h3>Explanation:</h3>

<u>We are given;</u>

  1. Mass of Lithium as 1.50 g
  2. Mass of nitrogen is 1.50 g

We are required to determine the rate limiting reagent.

  • First, we write the balanced equation for the reaction

6Li(s) + N₂(g) → 2Li₃N

From the equation, 6 moles of Lithium reacts with 1 mole of nitrogen.

  • Second, we determine moles of Lithium and nitrogen given.

Moles = Mass ÷ Molar mass

Moles of Lithium

Molar mass of Li = 6.941 g/mol

Moles of Li = 1.50 g ÷ 6.941 g/mol

                   = 0.216 moles

Moles of nitrogen gas

Molar mass of Nitrogen gas is 28.0 g/mol

Moles of nitrogen gas = 1.50 g ÷ 28.0 g/mol

                                     = 0.054 moles

  • According to the equation, 6 moles of Lithium reacts with 1 mole of nitrogen.
  • Therefore, 0.216 moles of lithium will require 0.036 moles (0.216 moles ÷6) of nitrogen gas.
  • On the other hand, 0.054 moles of nitrogen, would require 0.324 moles of Lithium.

Thus, Lithium is the limiting reagent while nitrogen is in excess.

7 0
3 years ago
In the following reaction, how many grams of ammonia (NH3) will react with 27.8 grams of nitric oxide (NO)? 4NH3 + 6NO → 5N2 + 6
Rzqust [24]
<span>4NH</span>₃<span> + 6NO → 5N</span>₂<span> + 6H</span>₂<span>O

mol of NO  =  </span>\frac{mass of NO}{Molar Mass of NO}
 
                  =  \frac{27.8 g}{30.01 g / mol}
                   
                  =  0.93 mol

Based on the balance equation mole ratio of NH₃  :  NO  is   4 : 6
                                                                                            =  2 : 3

If mol  of NO  =  0.93 mol

then mol of NH₃ = \frac{0.93 mol  *  2}{3}
                           
                          =  0.62 mol

Mass of ammonia =  mol  ×  molar mass
          
                             =  0.62 mol   ×  17.03 g/mol
 
                             =  10.54 g

Therefore B is the best answer





3 0
3 years ago
Read 2 more answers
In the reaction represented by the equation 2al2o3 ® 4al + 3o2, what is the mole ratio of the products aluminum and oxygen?
DerKrebs [107]
Answer:
4 : 3

Explanation:
The balanced chemical equation is given as follows:
2Al₂O₃ ..............> 4Al + 3O₂
Now, from this equation we can note that:
For every 4 moles of aluminum moles produced, corresponding 3 oxygen moles are produced.
This means that the ratio between the formation of aluminum to the formation of oxygen moles is 4:3

Hope this helps :)
4 0
3 years ago
Balance the reaction ____Mo+___O2&gt; ___MoO3​
DIA [1.3K]

The balanced reaction is: 2Mo+3O2>2MoO3

7 0
2 years ago
2. Which kind of model would you
steposvetlana [31]

Answer:

a. Physical model

3 0
2 years ago
Read 2 more answers
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