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Liula [17]
3 years ago
10

The following reactions have the indicated equilibrium constants at a particular temperature: N2(g) + O2(g) ⇌ 2NO(g) Kc = 4.3 ×

10−25 2NO(g) + O2(g) ⇌ 2NO2(g) Kc = 6.4 × 109 Determine the values of the equilibrium constants for the following equations at the same temperature: (a) 4NO(g) ⇌ N2(g) + 2NO2(g)
Chemistry
1 answer:
Anuta_ua [19.1K]3 years ago
3 0

Answer:

Kc=~1.49x10^3^4}

Explanation:

We have the reactions:

A: N_2_(_g_) + O_2_(_g_)  2NO_(_g_)~~~~~~Kc = 4.3x10^-^2^5

B: 2NO_(_g_)+~O_2_(_g_)~2NO_2_(_g_)~~~Kc = 6.4x10^9

Our <u>target reaction</u> is:

4NO_(_g_)  N_2_(_g_) + 2NO_2_(_g_)

We have NO_(_g_) as a reactive in the target reaction and  NO_(_g_) is present in A reaction but in the products side. So we have to<u> flip reaction A</u>.

A: 2NO_(_g_) N_2_(_g_) + O_2_(_g_) ~Kc =\frac{1}{4.3x10^-^2^5}

Then if we add reactions A and B we can obtain the target reaction, so:

A: 2NO_(_g_) N_2_(_g_) + O_2_(_g_) ~Kc =\frac{1}{4.3x10^-^2^5}

B: 2NO_(_g_)+~O_2_(_g_)~2NO_2_(_g_)~Kc=6.4x10^9

For the <u>final Kc value</u>, we have to keep in mind that when we have to <u>add chemical reactions</u> the total Kc value would be the <u>multiplication</u> of the Kc values in the previous reactions.

4NO_(_g_)  N_2_(_g_) + 2NO_2_(_g_)~~~Kc=\frac{6.4x10^9}{4.3x10^-^2^5}

Kc=~1.49x10^+^3^4}

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Answer:

See explanation

Explanation:

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With this in mind, for A in the last compound, we have <u>2 Br atoms</u> near to the acid carboxylic group, so, we will have a high inductive effect, then the C-H would be weaker and we will have <u>more acidity</u>. Then we will have the compound with only 1 Br atom and finally, the last compound would be the one without Br atoms.

In B, the difference between the molecules is the <u>position</u> of the "Br" atom in the molecule. If the Br atom is closer to the acid group we will have a <u>higher inductive effect</u> and more <u>acidity</u>.

See figure 1

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5 0
3 years ago
El hipoclorito de sodio (NaClO), es vendido en una solución clara de ligero color verde-amarillento y un olor característico que
vivado [14]

Respuesta:

16,7 mL

Explicación:

Paso 1: Información provista

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  • Volumen inicial (V₁): ?
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Paso 2: Calcular el volumen de la solución concentrada

Queremos preparar una solución diluida de hipoclorito de sodio a partir de una concentrada. Podemos calcular el volumen inicial que debemos tomar usando la regla de dilución.

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V₁ = C₂ × V₂ / C₁

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6 0
2 years ago
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3 years ago
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statuscvo [17]
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3 years ago
How many grams of calcium are required to free 8 grams of hydrogen gas from hydrochloride acid, HCl?
Gala2k [10]

Answer:

The answer to your question is 160 g of Calcium

Explanation:

Data

mass of Calcium = ?

mass of Hydrogen = 8 g

reactant = HCl

Process

1.- Write the balanced chemical reaction

             Ca  + 2HCl   ⇒   CaCl₂  +  H₂

2.- Look for the atomic number of Calcium and hydrogen

Calcium = 40 g

Hydrogen = 1 x 2 = 2 g

3.- Use proportions to calculate the mass of calcium needed.

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               x                      ----------------- 8 g of hydrogen

                         x = (8 x 40) / 2

                         x = 320/2

                         x = 160 g of Calcium

4 0
3 years ago
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