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Dmitriy789 [7]
3 years ago
15

Which has greater precision, the 10 ml graduated cylinder or the 50 ml graduated cylinder?

Chemistry
1 answer:
pychu [463]3 years ago
7 0
The cylinder with the greater precision is the 10 ml graduated cylinder.
Precision refers to the closeness of a measurement to the true value.
A 10 ml graduated cylinder will have greater precision because it has marks for every 2 ml, this will allow you to read your measurements to two significant figures.
The 50 ml graduated cylinder on the other hand has marks for every 1 ml, this graduation will only allow the user to record measurement up to one significant figure. And you know, the more the significant figures, the more precise the measurement are.
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Predict the products and then balance the equation
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Here's the balanced equation for given Double displacement reaction ~

\sf Pb(NO_3)_2 +2 \:  KI = PbI_2  +2 \:  KNO_3

The products fored are : Lead Iodide ( PbI2 ) and Potassium Nitrate ( KNO3 )

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2 years ago
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The following balanced equation shows the formation of water. 2H2 + O2 2H2O How many moles of oxygen (O2) are required to comple
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Answer:

13.7 moles of O₂ are needed

Explanation:

In order to find the moles of reactants that may react to make the products we need to determine the reaction:

Reactants are hydrogen and oxygen

Product: Water

2 moles of hydrogen can react to 1 mol of oxygen and produce 2 moles of water.

Balanced reaction: 2H₂(g) + O₂(g) →  2H₂O(l)

If 2 moles of hydrogen need 1 mol of oxygen to react

Therefore, 27.4 moles of H₂ must need (27.4 .1) / 2 = 13.7 moles of O₂

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3 years ago
The electrical current in a circuit is measured in which of the following units
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Answer:

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Which of the following is a negative effect of a volcano?
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Calculate the concentration of A bottle of wine contains 12.9% ethanol by volume. The density of ethanol (CH3OH) is 0.789 g/cm e
Delicious77 [7]

Answer:

The mass percentage of the solution is 10.46%.

The molality of the solution is 2.5403 mol/kg.

Explanation:

A bottle of wine contains 12.9% ethanol by volume.

This means that in 100 mL of solution 12.9  L of alcohol is present.

Volume of alcohol = v = 12.9 L

Mass of the ethanol = m

Density of the ethanol ,d= 0.789 g/cm^3=0.789 g/mL

1 cm^3=1 mL

m=d\times v=0.798 g/ml\times 12.9 mL = 10.1781 g

Mass of water = M

Volume of water ,V= 100 mL - 12.9 mL = 87.1 mL

Density of water = D=1.00 g/mL

M=D\times V=1.00 g/ml\times 87.1 mL =87.1 g

Mass percent

(w/w)\%=\frac{m}{m+M}\times 100

\frac{10.1781 g}{10.1781 g+87.1 g}\times 100=10.46\%

Molality :

m=\frac{m}{\text{molar mass of ethanol}\times M(kg)}

M = 87.1 g = 0.0871 kg (1 kg =1000 g)

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m=2.5403 mol/kg

4 0
3 years ago
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