Answer:
Proteins and nucleic acids
Explanation:
Nitrogen compounds in animals that are no longer of use, or are in access are excreted from the animals body, and are thus called nitrogenous waste. These nitrogenous waste can be excreted in three different ways.
1. Ammonia
2. Urea
3. Uric acid
For the given molecule, we are asked to give-
- The electron configuration of an isolated B atom
- The electron configuration of an isolated F atom
- Hybrid orbitals should be constructed on the B atom to make the B–F bonds in Boron tri flouride
- valence orbitals, if any, remain unhybridized on the B atom.
- The electron configuration of an isolated B atom:
as atomic number of B is 5
electronic configuration will be [He] 2s² 2p¹
- The electron configuration of an isolated F atom:
as atomic number of F is 9
electronic configuration will be [He] 2s² 2p5
- Hybrid orbitals should be constructed on the B atom to make the B–F bonds in Boron tri flouride will be sp2.
as the one s and two of p orbital from the valance shell will hybridised to make 3 hybrid orbital of B resulting in 3 B-F bonds.
- valence orbitals, if any, remain unhybridized on the B atom will be 1
To know more about hybrisisation:
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Answer:
it forms :
1. Gold ( Au )
2. Zinc nitrate ( Zn(NO3)2 )
Explanation:
When a chunk of zinc is added to a solution of gold (III) nitrate to extract the gold. The reaction forms Gold and Zinc nitrate .
it's a single displacement reaction,
here's the balanced equation for above reaction :
3 Zn + 2 Au(NO3)3 =》3 Zn(NO3)2 + 2 Au
It’s C I think and I’m not sure
The chemical properties, chemical reactivity
