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tangare [24]
2 years ago
7

Mention 20 products of carbon​

Chemistry
1 answer:
den301095 [7]2 years ago
4 0

Answer:

1. Diamonds

2. Graphite

3. Textiles

4. Life Itself

5. Coal

6. Graphene

7. Carbon Dioxide

8. Coca-Cola

9. Paintball Guns

10. White dwarf stars

11. Oil

12. Gasoline

13. Curede oil

14. Wood (almost all fibers used for clothes contain carbon, as they are either proteins from animals/plants, or they are plastics.)

15. Acetic acid.

16. Acetylene.

17. Benzeze.

18. Carbon dioxide.

19. Carbon disulfide.

20. Carbon monoxide.

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Physical properties of earth metals-
Liula [17]

Answer:

Properties of Alkaline Earth Metals

shiny.

silvery-white.

somewhat reactive metals at standard temperature and pressure.

readily lose their two outermost electrons to form cations with a 2+ charge.

low densities.

low melting points.

low boiling points.

Explanation:

4 0
2 years ago
What is the result of adding 2.5 × 10³ and 3.5 × 10²?
Elanso [62]

Answer:

A

Explanation:

It is correct please I hope it helps! :)

7 0
3 years ago
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What depends on public opinion and support? A. regulations at a local level B. enforcement of laws C. success of a policy D. rev
Nastasia [14]

i believe the answer is success of a policy. if this was correct please mark brainliest and lmk if you have any more questions x

3 0
3 years ago
Can someone help me with this​
Alexxx [7]

Answer:

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Explanation:

8 0
3 years ago
If I had 3.50 x 10 24molecules of Cl2 gas, how many grams is this?
Zinaida [17]

Answer:

412 g Cl₂

General Formulas and Concepts:

<u>Atomic Structure</u>

  • Reading a Periodic Table
  • Moles
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Stoichiometry</u>

  • Using Dimensional Analysis

Explanation:

<u>Step 1: Define</u>

[Given] 3.50 × 10²⁴ molecules Cl₂

[Solve] grams Cl₂

<u>Step 2: Identify Conversions</u>

Avogadro's Number

[PT] Molar Mass of Cl - 35.45 g/mol

Molar Mass of Cl₂ - 2(35.45) = 70.9 g/mol

<u>Step 3: Convert</u>

  1. [DA] Set up:                                                                                                       \displaystyle 3.50 \cdot 10^{24} \ molecules \ Cl_2(\frac{1 \ mol \ Cl_2}{6.022 \cdot 10^{23} \ molecules \ Cl_2})(\frac{70.9 \ g \ Cl_2}{1 \ mol \ Cl_2})
  2. [DA] Divide/Multiply [Cancel out units]:                                                           \displaystyle 412.072 \ g \ Cl_2

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

412.072 g Cl₂ ≈ 412 g Cl₂

5 0
3 years ago
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