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3 years ago

Which of the following is not a concentration unit (a) 1 molar (b) 1 equivalent (c) 1% by mass (d) 1 molal

Chemistry

1 answer:

musickatia [10]3 years ago

6 0

Answer:

(b) 1 equivalent

Step-by-step explanation:

Concentration is the relative amount of a substance in a given volume or mass of something else.

An equivalent is not a concentration, because it is just a mass —the mass of a substance needed to react with or supply one gram of hydrogen.

(a) is wrong. 1 M means that there is 1 mol of a substance in 1 L of solution.

(d) is wrong. 1 m means that there is 1 mol of a substance in 1 kg of solvent.

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2 years ago

What are the oxides of oxygen

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2 years ago

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Give the name and symbol of the prefixes used with SI units to indicate multiplication by the following exact quantites.

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Answer:

A. Kilo , K, multiplication by 1000

B. Centi, c

C. Deci, d

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3 years ago

Suppose that 0.1000 mole each of H2and I2are placed in a 1.000-L flask, stoppered, and the mixture is heated to 425oC. At equili

Katen [24]

Answer: The value of equilibrium constant for the given reaction is 56.61

Explanation:

We are given:

Initial moles of iodine gas = 0.100 moles

Initial moles of hydrogen gas = 0.100 moles

Volume of container = 1.00 L

Molarity of the solution is calculated by the equation:

$\text{Molarity of solution}=\frac{\text{Number of moles}}{\text{Volume}}$

$\text{Molarity of iodine gas}=\frac{0.1mol}{1L}=0.1M$

$\text{Molarity of hydrogen gas}=\frac{0.1mol}{1L}=0.1M$

Equilibrium concentration of iodine gas = 0.0210 M

The chemical equation for the reaction of iodine gas and hydrogen gas follows:

$H_2+I_2\rightleftharpoons 2HI$

Initial: 0.1 0.1

At eqllm: 0.1-x 0.1-x 2x

Evaluating the value of 'x'

$\Rightarrow (0.1-x)=0.0210\\\\\Rightarrow x=0.079M$

The expression of $K_c$ for above equation follows:

$K_c=\frac{[HI]^2}{[H_2][I_2]}$

$[HI]_{eq}=2x=(2\times 0.079)=0.158M$

$[H_2]_{eq}=(0.1-x)=(0.1-0.079)=0.0210M$

$[I_2]_{eq}=0.0210M$

Putting values in above expression, we get:

$K_c=\frac{(0.158)^2}{0.0210\times 0.0210}\\\\K_c=56.61$

Hence, the value of equilibrium constant for the given reaction is 56.61

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3 years ago

I don't quite understand it

irina1246 [14]

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2 years ago