What are the uses of chemistry?

Chemistry

1 answer:

devlian [24]3 years ago

4 0

Answer:

Chemistry is the study of matter , its properties,how and why substance combine or separate to form other substance.

It's uses are

1) It is used in health care and beauty

2) Industries and transportation

3) Agriculture, science and technology

4) Cooking , cleaning, medicines etc

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Calculate the morality of a 35.4% (by mass) aqueous solution of phosphoric acid (H3PO4). Molar mass of H3PO4 is 98.00g/mol

Butoxors [25]

Answer:

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3 years ago

Imagine a small synthetic vesicle made from pure phospholipids enclosing an interior lumen containing 1 mM glucose and 1 mM sodi

Alexeev081 [22]

Answer:

C. H2O diffuses in.

Explanation:

<em>The phospholipids-made synthetic vesicle in this case will act like a semi-permeable membrane while the solution in the interior lumen will be hypertonic to the surrounding pure water. </em>

<em>Hence, water molecules will diffuse into the lumen through the semi-permeable membrane because of the osmotic gradient that exist between the internal and the surrounding solution of the vesicle.</em>

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4 years ago

Consider 5.00 L of a gas at 365 mmHg and 20. ∘C . If the container is compressed to 2.30 L and the temperature is increased to 4

lakkis [162]

Answer:

P₂ = 1.12 atm

Explanation:

To find the new pressure, you need to use the Combined Gas Law:

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

In this equation, "P₁", "V₁", and "T₁" represent the initial pressure, volume, and temperature. "P₂", "V₂", and "T₂" represent the new pressure, volume, and temperature. Before plugging the values into the equation, you need to

(1) convert the pressure from mmHg to atm (760 mmHg = 1 atm)

(2) convert the temperatures from Celsius to Kelvin (°C + 273)

The final answer should have 3 sig figs like the given values.

P₁ = 365 mmHg / 760 = 0.480 atm P₂ = ? atm

V₁ = 5.00 L V₂ = 2.30 L

T₁ = 20°C + 273 = 293 K T₂ = 40°C + 273 = 313 K

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$ <----- Combined Gas Law

$\frac{(0.480 atm)(5.00 L)}{293 K}=\frac{P_2(2.30 L)}{313 K}$ <----- Insert values