All categories

3 years ago

Which of the following is a scalar? centripetal force weight speed acceleration

Physics

2 answers:

andreyandreev [35.5K]3 years ago

7 0

Answer:

Speed

Explanation:

- A scalar quantity is defined as a quantity which has a magnitude only (no direction)

- A vector quantity is defined as a quantity which has both a magnitude and a direction

Let's analyze each option:

- Centripetal force: force is a vector, because it has a magnitude and also a direction

- Weight: weight is a force, and force are vector quantities, so weight is a vector as well

- Speed: speed is a scalar quantity, because it has only a magnitude, no direction

- Acceleration: acceleration is a vector quantity, because it has a magnitude, but also a direction (because it represents the rate of charge in velocity, and since velocity is a vector, acceleration must be a vector as well)

So, the correct choice is

Speed

choli [55]3 years ago

6 0

Scalar is a quantity such as mass or length that is completely determined by its own magnitude and has no direction. Therefore, your answer is Speed.

You might be interested in

Can something change states of matter how do you know

belka [17]

Yes, it can change states of matter from heat. Like ice, ice changes it’s state of matter from the temperature it is in, which causes it to turn into a liquid.(another form of matter) Again with heat, if water is boiled to a certain temperature it converts to a gas. Now with cold. If water is at such a coke temperature it will turn to ice, a form of matter. Now when a gas is cooled down, the atoms comprising the gas have less energy to move around.

4 0

3 years ago

Having landed on a newly discovered planet, an astronaut sets up a simple pendulum of length 1.38 m and finds that it makes 441

Tasya [4]

The period of a simple pendulum is given by:
$T=2 \pi \sqrt{ \frac{L}{g} }$
where L is the pendulum length, and g is the gravitational acceleration of the planet. Re-arranging the formula, we get:
$g= \frac{4 \pi^2}{T^2}L$ (1)

We already know the length of the pendulum, L=1.38 m, however we need to find its period of oscillation.

We know it makes N=441 oscillations in t=1090 s, therefore its frequency is
$f= \frac{N}{t}= \frac{441}{1090 s}=0.40 Hz$
And its period is the reciprocal of its frequency:
$T= \frac{1}{f}= \frac{1}{0.40 Hz}=2.47 s$

So now we can use eq.(1) to find the gravitational acceleration of the planet:
$g= \frac{4 \pi^2}{T^2}L = \frac{4 \pi^2}{(2.47 s)^2} (1.38 m) =8.92 m/s^2$

3 0

3 years ago

Is the universe infinite

Softa [21]

Answer:

The observable universe is still huge, but it has limits. because it's most likely like an plane all round.

Explanation:

6 0

3 years ago

Read 2 more answers

:What will be the value of the refractive index of the medium? Critical angle of that medium is 30 degree

earnstyle [38]

Answer:

Let the second medium be air (n₁=1)

The refractive index n₂ of the medium where first medium is air is found (a)

(a) n₂ = 2

Explanation:

Critical angle can be defined as the angle of incidence that provides the angle of refraction of 90°.

Refractive index of a medium can be defined as a number that describes that how fast a light will travel through that medium.

Critical angle and Refractive index are related by:

$\theta_{critical}= sin^{-1}(\frac{n_1}{n_2})$

$sin \theta_{critical}=\frac{n_1}{n_2}$

To find refractive index of medium with respect to air, substitute n₁=1 (Refractive index of air is 1)

Also θ(critical)=30°

Find n₂ :

$sin30= \frac{1}{n_2}\\0.5=\frac{1}{n_2}\\n_2=\frac{1}{0.5}\\n_2=2$

8 0

2 years ago

The robot arm is elevating and extending simultaneously. At a given instant, θ = 30°, ˙ θ = 10 deg / s = constant θ˙=10 deg/s=co

motikmotik

Explanation:

The position vector r:

$\overrightarrow{r(t)}=lcos\theta\hat{i}+lsin\theta\hat{j}$

The velocity vector v:

$\overrightarrow{v(t)}=\overrightarrow{\frac{dr}{dt}}=\dot{l}cos\theta-lsin\theta\dot{\theta}\hat{i}+\dot{l}sin\theta+lcos\theta\dot{\theta}\hat{j}$

The acceleration vector a:

$\overrightarrow{a(t)}}=cos\theta(\ddot{l}-l\dot{\theta}^2)-sin\theta(2\dot{l}\dot{\theta}+l\ddot{\theta})\hat{i}+cos\theta(2\dot{l}\dot{\theta}+l\ddot{\theta})+sin\theta(\ddot{l}-l\dot{\theta}^2)\hat{j}$

$\overrightarrow{v(t)}=0.13\hat{i}+0.18\hat{j}$

$\overrightarrow{a(t)}}=-0.3\hat{i}-0.1\hat{j}$

5 0

2 years ago