Answer:
b
every magnet is made of many aligned smaller magnets
Explanation:
Hysical science is defined as the study of observable phenomena in the universe.
<span>the main idea of physical science is known as the "scientific method". </span>
<span>this method states: </span>
<span>observe a "real" ( not imaginary ) phenomena. </span>
<span>make a hypothesis ( or theory / idea ) that EXPLAINS this phenomena. </span>
<span>conduct a real experiment to test this hyothesis. </span>
<span>confirm that the experiment validates the original hypothesis and if necessary amend the theory. </span>
<span>it has worked so well that the very communication you are having with me is a result of the wonders of physical science. </span>
Answer:
Mg will replace Ag in a compound
Explanation:
A single replacement reaction is driven by the position of ions on the activity series.
As a rule of thumb, the position of metal ions on the activity series determines their reactivity.
Metal ions that are above another are more reactive and they will displace those that are lower.
Generally, activity increases as we go up the group.
Mg ions are higher than Ag ions on the series so, Mg will displace Ag from a solution.
The force acting on the object is constant, so the acceleration of the object is also constant. By definition of average acceleration, this acceleration was
<em>a</em> = ∆<em>v</em> / ∆<em>t</em> = (6 m/s - 0) / (1.7 s) ≈ 3.52941 m/s²
By Newton's second law, the magnitude of the force <em>F</em> is proportional to the acceleration <em>a</em> according to
<em>F</em> = <em>m a</em>
where <em>m</em> is the object's mass. Solving for <em>m</em> gives
<em>m</em> = <em>F</em> / <em>a</em> = (10 N) / (3.52941 m/s²) ≈ 2.8 kg
A) 
The energy of an x-ray photon used for single dental x-rays is
The energy of a photon is related to its wavelength by the equation
where
is the Planck constant
is the speed of light
is the wavelength
Re-arranging the equation for the wavelength, we find
B) 
The energy of an x-ray photon used in microtomography is 2.5 times greater than the energy of the photon used in part A), so its energy is
And so, by using the same formula we used in part A), we can calculate the corresponding wavelength:
