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Nadusha1986 [10]
4 years ago
13

A stunt driver rounds a banked, circular curve. The driver rounds the curve at a high, constant speed, such that the car is just

on the verge of skidding to the outside of the curve. A front view of a car driving on a banked curve. The cross section of the banked road is constructed like a ramp. The car drives transversely to the slope of the ramp, so that the wheels of one side of the car are lower than the wheels on the other side of the car. Which forces are directly responsible for producing the car’s centripetal acceleration? Coriolis force centripetal force frictional force normal force gravitational force
Physics
1 answer:
bagirrra123 [75]4 years ago
5 0

Answer: C

Frictional force

Explanation:

The description of the question above is an example of a circular motion.

For a car travelling in a curved path, the frictional force between the tyres and the road surface will provide the centripetal force.

Since the road is banked, and the cross section of the banked road is constructed like a ramp. The car drives transversely to the slope of the ramp, so that the wheels of one side of the car are lower than the wheels on the other side of the car, for cornering the banked road, the car will not rely only on the frictional force.

Therefore, the correct answer is option C - the frictional force.

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3 years ago
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How much energy is needed to heat and melt 3.0 kg of copper initially at 83°C?
Ne4ueva [31]

As we know that in order to melt the copper we need to take the temperature of copper to its melting point

So here heat required to raise the temperature of copper is given as

Q = ms\Delta T

We know that

melting temperature of copper = 1085 degree C

Specific heat capacity of copper = 385 J/kg C

now we have

Q = 3(385)(1085 - 83)

Q = 1157310 J

Q = 1157.3 kJ

now in order to melt the copper we know the heat required is

Q = mL

here we know that

L = 205 kJ/kg

now from above formula

Q = 3(205) kJ

Q = 615 kJ

now total heat required will be

Q = 1157.3 kJ + 615 kJ

Q = 1772.3 kJ

As we know that

1 Cal = 4.18 kJ

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6 0
3 years ago
Define time period. Give its formula. ​
kondaur [170]

Answer:

Part A

Time period, designated by the symbol, 'T', is defines as the time it takes for a complete cycle of an oscillation or vibration (of a wave) to transit through a given point.

The longer the time period of a wave, the lower the frequency of the wave

The unit of the time period is seconds, 's'

Part B

Mathematically, the formula for the time period is presented as follows;

f = 1/T

∴ T = 1/f

f = v/λ

∴ T = λ/v

Where;

v = The velocity of the wave;

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Explanation:

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3 years ago
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Answer:

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Explanation:

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The peak emf is:

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Substituting w=2\pi f and the value for peaf E gives:

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Hence, wire's length is 171.43m

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