The box moved 0.73 m
<u>Explanation:</u>
Given data,
Magnitude 8.1 N Work on the box 5.9 J Clerk move a 4.4 Kg
Distance= work done on the box / Horizontal force on the magnitude
= 5.9/8.1
=0.728
Distance =0.73 m
The box moved 0.73 m
I’d say it’s 8 or 80
Hopefully this helps sorry
Displace/time=velo
8000/12 = 666.666666667 speed
Answer:
Explanation:
From the question we are told that
The length of the string is 
The mass of the string is 
The distance from the bridge to the support post 
The tension is 
Generally the frequency is mathematically represented as
![v = \frac{n}{2 * L } [\sqrt{ \frac{T}{\mu} } ]](https://tex.z-dn.net/?f=v%20%20%3D%20%20%5Cfrac%7Bn%7D%7B2%20%2A%20L%20%7D%20%20%5B%5Csqrt%7B%20%5Cfrac%7BT%7D%7B%5Cmu%7D%20%7D%20%5D)
Where n is and integer that defines that overtones
i.e n = 1 is for fundamental frequency
n = 2 first overtone
n =3 second overtone
Also 
is the linear density of the string which is mathematically represented as
=> 
=> 
So for n = 1
![v_1 = \frac{1}{2 * 0.62 } [\sqrt{ \frac{ 540}{0.003889} } ]](https://tex.z-dn.net/?f=v_1%20%20%3D%20%20%5Cfrac%7B1%7D%7B2%20%2A%20%200.62%20%7D%20%20%5B%5Csqrt%7B%20%5Cfrac%7B%20540%7D%7B0.003889%7D%20%7D%20%5D)
So for n = 2
![v_2 = \frac{2}{2 * 0.62 } [\sqrt{ \frac{ 540}{0.003889} } ]](https://tex.z-dn.net/?f=v_2%20%20%3D%20%20%5Cfrac%7B2%7D%7B2%20%2A%20%200.62%20%7D%20%20%5B%5Csqrt%7B%20%5Cfrac%7B%20540%7D%7B0.003889%7D%20%7D%20%5D)
So for n = 3
![v_3 = \frac{3}{2 * 0.62 } [\sqrt{ \frac{ 540}{0.003889} } ]](https://tex.z-dn.net/?f=v_3%20%20%3D%20%20%5Cfrac%7B3%7D%7B2%20%2A%20%200.62%20%7D%20%20%5B%5Csqrt%7B%20%5Cfrac%7B%20540%7D%7B0.003889%7D%20%7D%20%5D)
<h3>
Answer: B) his muscles</h3>
Explanation:
Specifically his leg muscles. As the leg muscles expand, they push down on the ground. Newton's 3rd law says that for any action, there's an opposite and equal reaction. That means a downward push into the ground will have the ground push back, more or less, and that's why the kangaroo will jump. The ground (and the earth entirely) being much more massive compared to the animal means that the ground doesn't move while the kangaroo does move. Perhaps on a very microscopic tiny level the ground/earth does move but it's so small that we practically consider it 0.
This experiment can be done with a wall as well. Go up to a wall and lean against it with your hands. Then do a pushup to move further away from the wall, but you don't necessarily need to lose contact with the wall's surface. As you push against the wall, the wall pushes back, and that causes you to move backward. If the wall was something flimsy like cardboard, then you could easily push the wall over and you wouldn't move back very much. It all depends how much mass is in the object you're pushing on.
