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Nostrana [21]
3 years ago
7

The atomic nucleus contains two subatomic particles, the proton and the neutron. Atoms of different elements have different numb

ers of protons and neutrons. The nuclei of atoms that are the most stable have proton to neutron ratios of:
A) 1 to 1
B) 2 to 1
C) 1 to 2
D) there is no pattern that indicates stability in the nucleus
Physics
2 answers:
9966 [12]3 years ago
7 0
The answer is option A .

Step2247 [10]3 years ago
5 0

the correct answer is the letter A)1 to 1

You might be interested in
How to solve god initial speed
CaHeK987 [17]

Answer:

Velocity is a function of time and defined by both a magnitude and a direction. [1] Often in physics problems, you will need to calculate the initial velocity (speed and direction) at which an object in question began to travel. There are multiple equations that can be used to determine initial velocity. Using the information given in a problem, you can determine the proper equation to use and easily answer your question.

This is from a website btw.

4 0
3 years ago
"An empty cylindrical barrel is open at one end and rolls without slipping straight down a hill. The barrel has a mass of 19.0 k
Sophie [7]

Answer:

the acceleration due to gravity, g of the cylinder is 9.81m/s2

Explanation:

since the cylinder is rolling down from a hill, the acceleration due to gravity of any object coming down from the atmosphere is always constant which is g=9.8m/s2 or approximately 10m/s2

5 0
3 years ago
A car that weighs 1.0 x 10^4 N is initially moving at a speed of 38 km/h when the brakes are applied and the car is brought to a
hram777 [196]

Answer:

Part a) Force on car = 2833.84 Newtons

Part b) Time to stop the car = 3.8 seconds

Part c) Factor for stopping distance is 4.

Part d) Factor for stopping time is 1.

Explanation:

The deceleration produced when the car is brought to rest in 20 meters can be found by third equation of kinematics as

v^2=u^2+2as

where

v = final speed of the car ( = 0 in our case since the car stops)

u = initial speed of the car = 38 km/hr =\frac{38\times 1000}{3600}=10.56m/s

a = deceleration produces

s = distance in which the car stops

Applying the given values we get

0^2=10.56^2+2\times a\times 20\\\\a=\frac{0-10.56^2}{2\times 20}\\\\\therefore a=-2.78m/s^2

Now the force can be obtained using newton's second law as

Force=\frac{Weight}{g}\times a

Applying values we get

Force=\frac{1.0\times 10^4}{9.81}\times -2.78\\\\\therefore F=-2833.84Newtons

The negative direction indicates that the force is opposite to the motion of the object.

Part b)

The time required to stop the car can be found using the first equation of kinematics as

v=u+at with symbols having the same meanings

Applying values we get

0=10.56-2.78\times t\\\\\therefore t=\frac{10.56}{2.78}=3.8seconds

Part c)

From the developed relation of stopping distance we can see that the for same force( Same acceleration) the stopping distance is proportional to the square of the initial speed thus doubling the initial speed increases the stopping distance 4 times.

Part d)

From the relation of stopping time and the initial speed we can see that the stopping distance is proportional initial speed thus if we double the initial speed the stopping time also doubles.

8 0
3 years ago
1) A net force of 75.5 N is applied horizontally to slide a 225 kg crate across the floor.
dimulka [17.4K]

Answer:

The acceleration of the crate is 0.3356\,\frac{m}{s^2}

Explanation:

Recall the formula that relates force,mass and acceleration from newton's second law;

F=m\,a

Then in our case, we know the force applied and we know the mass of the crate, so we can solve for the acceleration as shown below:

F=m\,a\\75.5\,N=225\,\,kg\,\,a\\a=\frac{75.5}{225} \,\frac{m}{s^2} \\a=0.3356\,\,\frac{m}{s^2}

7 0
3 years ago
(e) For photons of energy 7.10 eV, what stopping potential would be required to arrest the current of photoelectrons
Masja [62]

2.37eV stopping potential would be required to arrest the current of photoelectrons.

<h3 /><h3>What is stopping potential ?</h3>

The minimal negative voltage that must be provided to the anode to halt the photocurrent is known as stopping potential. When expressed in electron volts, the maximal kinetic energy of the electrons is equal to the stopping voltage.

Kmax = eV₀

2.37eV = eV₀

V₀ = 2.37eV

to learn more about stopping potential go to - brainly.com/question/4655588

#SPJ4

8 0
2 years ago
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