Consider the video tutorial you just watched. Suppose that we duplicate this experimental setup in an elevator. What will the sp
ring scale read if the elevator is moving upward at constant speed?
1 answer:
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Answer:
a) The strength of gravity decreases if one moved away from Jupiter
b) The strength of gravity increases if one fell into Jupiter
Explanation:
The gravitational attraction is given by Newton law of gravitation as follows;
Where;
G = The universal gravitational constant = 6.67408 × 10⁻¹¹ m³/(kg·s²)
M = The mass of Jupiter
m = The mass of the nearby body
R = The distance between the centers of Jupiter and the body
From the equation, we have that the gravitational strength varies inversely with the square of the separation distance between two bodies
Therefore, as one moves away, R increases, and the strength of gravity reduces
Similarly as the body falls into Jupiter, R, reduces the gravitational strength increases.
Answer:
the force P required for impending motion is 132.3 N
the largest value of "h" allowed if the cabinet is not to tip over is 0.8 m
Explanation:
Given that:
mass of the cabinet m = 45 kg
coefficient of static friction μ = 0.30
A free flow body diagram illustrating what the question represents is attached in the file below;
The given condition from the question let us realize that ; the casters are locked to prevent the tires from rotating.
Thus; considering the forces along the vertical axis ; we have :
The upward force and the downward force is :
where;
are the normal contact force at center point A and B respectively .
------- equation (1)
Considering the forces on the horizontal axis:
where ;
are the static friction at center point A and B respectively.
which can be written also as:
replacing our value from equation (1)
P = 0.30 ( 441)
P = 132.3 N
Thus; the force P required for impending motion is 132.3 N
b) Since the horizontal distance between the casters A and B is 480 mm; Then half the distance = 480 mm/2 = 240 mm = 0.24 cm
the largest value of "h" allowed for the cabinet is not to tip over is calculated by determining the limiting condition of the unbalanced torque whose effect is canceled by the normal reaction at and it is shifted to
:
Then:
h = 0.8 m
Thus; the largest value of "h" allowed if the cabinet is not to tip over is 0.8 m
here as it is given that x component of the vector is positive while y component of the vector is negative so we can say the vector must inclined in Fourth quadrant.
So angle must be more than 270 degree and less than 360 degree
Now in order to find the value we can say that
so it is inclined at above angle with X axis in fourth quadrant
Now if angle is to be measured counterclockwise then its magnitude will be
so the correct answer will be 305 degree