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Anna [14]
4 years ago
7

A rural mail carrier is driving slowly, putting mail in mailboxes near the road

Physics
1 answer:
kow [346]4 years ago
4 0

Incomplete question. I inferred you want access to the full question.

Explanation:

A rural mail carrier is driving slowly, putting mail in mailboxes near the road. He overshoots one mailbox, stops, shifts into reverse, and then backs up until he is at the right spot. The velocity graph given below represents his motion.

a. draw the mail carrier's position vs time graph. Assume that x = 0 m at t = 0 s.

b. what is the position of the mailbox?

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PLEASE HURRY!!!!!!! A sample of gas does 150J of work against its surroundings and loses 90J of internal energy in the process.
olga_2 [115]

Answer:

the heat gained by the system (gas) is 60 J.

Explanation:

Given;

work done by the gas sample, W = 150 J

change in internal energy, ΔU = -90 J

Apply the first law of thermodynamic;

ΔU = Q - W

where;

Q is the heat gained by the system

From the equation above;

Q = ΔU + W

Q = -90 + 150

Q = 60 J

Therefore, the heat gained by the system (gas) is 60 J.

3 0
3 years ago
City A and City B are located far apart at the same latitude. City A has a much greater annual temperature range than City B. Th
Oksana_A [137]

Answer:

a). is lower in elevation than city B                                

Explanation:

Temperature of a place greatly varies with height or altitudes.

As we go higher the atmospheric pressure becomes less and the temperature decreases. We feel cold at higher altitude places and relatively hot at places of lower elevation. Therefore City A which is at lower elevation  has  greater annual temperature range than the temperature range of city B although they are located at the same latitude. City A is at lower altitude and City B's elevation is higher. So City A has higher temperature range than city b.

7 0
4 years ago
A 69-kg student sitting on a hardwood floor does not slide until pulled by a 260-N horizontal force. find coefficient of frictio
salantis [7]

Answer:

μ = 0.385

Explanation:

Given that,

The mass of the student, m = 69 Kg

The horizontal force applied, F = 260 N

The normal force acting on the body, weight = mg = 69g  N

                                                                                    = 676.2 N

The coefficient of friction acting on a body is equal to the force acting on the body to the normal force acting on the body due to gravitation.

The formula for coefficient of friction,

                                    μ =  F / N

Substituting the values in the above equation,

                                     μ = 260 N / 676.2 N

                                        = 0.385

Hence, the  coefficient of friction, μ = 0.385

6 0
3 years ago
Using .125 mass kgwhat is the velocity​
agasfer [191]

Answer:

The answer is 5 meters per second.

6 0
3 years ago
The stationary object from which movement is
Fynjy0 [20]

Answer:

I believe that the correct answer is D. reference point.

6 0
3 years ago
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