To decrease an amount by 18%, what single multiplier would you use?
2 answers:
Answer:
0.82
Step-by-step explanation:
We are asked to find the single multiplier used to show an amount decreased by 18%.
Since amount is decreasing by 18%, this means that 82% (100-18) of the amount is remaining.
The multiplier will be in decimal form, so we will convert 82% to decimal as:
Therefore, our required single multiplier is 0.82.
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Answer:
0.50 kg of the material would be left after 10 days.
0.25 kg of the material would be left after 20 days.
Step-by-step explanation:
We have been given that the half-life of a material is 10 days. You have one 1 kg of the material today. We are asked to find the amount of material left after 10 days and 20 days, respectively.
We will use half life formula.
, where,
A = Amount left after t units of time,
a = Initial amount,
t = Time,
h = Half-life.
Therefore, amount of the material left after 10 days would be 0.5 kg.
Therefore, amount of the material left after 20 days would be 0.25 kg.
The compound interest formula is :
where, A= Future value including the interest,
P= Principle amount, r= rate of interest in decimal form,
t= number of years and n= number of compounding in a year
Here, in this problem P= $ 51,123.21 , t= 20 years and 2 months
So, t= 20 + (2/12) years
t= 20 + 0.17 = 20.17 years
As the amount is compounded daily, so n= (12×30)= 360 [Using the traditional Banker’s rule of 30 days per month]
Thus,
When the interest rate is given, then we can use this equation for finding the future value.
Answer:
1 2/4
Step-by-step explanation:
3/4 doubled is
Now, on simplification.
Therefore,
3/4 doubled is 1 2/4