Answer:
2 days 5 minuts 14 seconds
Step-by-step explanation:
1 1 1 1 1
18 19 26
+25 45 48
1 24 05 14
The volume is 4.19ft³ Hope it helps <3
Answer:
Step-by-step explanation:
given that the Chocolate House specializes in hand-dipped chocolates for special occasions. Three employees do all of the product packaging
Clerk I II III total
Pack 0.33 0.23 0.44 1
Defective 0.02 0.025 0.015
Pack&def 0.0066 0.00575 0.0066 0.01895
a) probability that a randomly selected box of chocolates was packed by Clerk 2 and does not contain any defective chocolate
= P(II clerk) -P(II clerk and defective) = 
b) the probability that a randomly selected box contains defective chocolate=P(I and def)+P(ii and def)+P(iiiand def)
=0.01895
c) Suppose a randomly selected box of chocolates is defective. The probability that it was packaged by Clerk 3
=P(clerk 3 and def)/P(defective)
=
Answer:

Step-by-step explanation:
To find the 5th term in the expansion, we first will need to apply the binomial theorem. I have attached an image of the binomial theorem formula due to not being able to type it.
After applying the binomial theorem and simplifying, you should get:

Our 5th term here is:
which is equal to 
~Hope this helps! Sorry if my answer is confusing at all, it's pretty difficult to explain.~
Answer:
(0, 1)
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
<u>Algebra I</u>
- Solving systems of equations using substitution/elimination
Step-by-step explanation:
<u>Step 1: Define Systems</u>
y + 5x = 1
5y - x = 5
<u>Step 2: Rewrite Systems</u>
y + 5x = 1
- Subtract 5x on both sides: y = 1 - 5x
<u>Step 3: Redefine Systems</u>
y = 1 - 5x
5y - x = 5
<u>Step 4: Solve for </u><em><u>x</u></em>
<em>Substitution</em>
- Substitution in <em>y</em>: 5(1 - 5x) - x = 5
- Distribute 5: 5 - 25x - x = 5
- Combine like terms: 5 - 26x = 5
- Isolate <em>x</em> term: -26x = 0
- Isolate <em>x</em>: x = 0
<u>Step 5: Solve for </u><em><u>y</u></em>
- Define equation: 5y - x = 5
- Substitute in <em>x</em>: 5y - 0 = 5
- Subtract: 5y = 5
- Isolate <em>y</em>: y = 1