Answer:
K.E₂ = mg(h - 2R)
Explanation:
The diagram of the car at the top of the loop is given below. Considering the initial position of the car and the final position as the top of the loop. We apply law of conservation of energy:
K.E₁ + P.E₁ = K.E₂ + P.E₂
where,
K.E₁ = Initial Kinetic Energy = (1/2)mv² = (1/2)m(0 m/s)² = 0 (car initially at rest)
P.E₁ = Initial Potential Energy = mgh
K.E₂ = Final Kinetic Energy at the top of the loop = ?
P.E₂ = Final Potential Energy = mg(2R) (since, the height at top of loop is 2R)
Therefore,
0 + mgh = K.E₂ + mg(2R)
<u>K.E₂ = mg(h - 2R)</u>
<h3><u>Answer;</u></h3>
= 64 N/m
<h3><u>Explanation</u>;</h3>
According to Hooke's Law for a helical spring or an elastic material, extensional force is directly proportional to the distance the material has extended.
F = ke; where F is the extension force, k is the spring constant, and e is the distance extended.
Thus;
k = F/e
= 44N/0.69 m
= 63.768 N/m
<u>= 64 N/m</u>
Answer: C) divide: distance ÷ velocity
Explanation:
The velocity
equation is distance
divided by time
:

If we isolate
we will have:

Hence, the correct option is C: distance divided by velocity.
Answer:By turning the electrical current off
Explanation:Trust me I took the test