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3 years ago

Pendulum takes 1 second to move from x to y so it's frequency equal

1 answer:

5 0

if it takes 1 second to move from x to y. You haven't specified if x and y are extreme point or x is extreme and y is equilibrium point

I.If both are extreme points the period is T=1*2=2s

f(frequency)=2π/T(period)

f=6.28/2=3.14Hz

II.If x is an extreme point and y is equilibrium

T=4*1=4s

f=6.28/4=1.57Hz

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3 years ago

A rope is vibrating in such a manner that three equal-length segments are found to be vibrating up and down with 321 complete cy

kolbaska11 [484]

Answer:

<u>2.48 m</u> is the length of the rope.

Explanation:

Cycle period is 321

Time is 20 second

Wave travels at speeds = 26.4 m/s

We know that,

$\text { Frequency }=\frac{1}{T} \text { (For one cycle) }$

Frequency required for 321 complete cycle in 20 seconds is

$\text { Frequency }(f)=\frac{321}{20}$

Frequency = 16.05 hz

We know that,

$\text { Wavelength }=\frac{\text { wave velocity }}{\text { frequency }}$

$\lambda=\frac{v}{f}$

λ = wavelength, the distance between "wave crests" (m)

v = wave velocity, the "speed" that waves are moving in a direction (m/s)

f = frequency, (cycles/ or Hz)

$\lambda=\frac{26,4}{16.05}$

λ = 1.65 m

As per given question "length of the rope has three equal length segment"

$\mathrm{Length of the rope}=\frac{3}{2} \lambda$

$\mathrm{Length of the rope }=\frac{3}{2} \times 1.65$

$\mathrm{Length of the rope}=1.5 \times 1.65$

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3 years ago

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4 years ago

A sanding disk with rotational inertia 3.8 x 10-3 kg·m2 is attached to an electric drill whose motor delivers a torque of magnit

Elis [28]

Answer:

(a) Angular momentum of disk is $1.343\, \frac{kg.m^{2}}{s}$

(b) Angular velocity of the disk is $353\frac{rad}{s}$

Explanation:

Given

Rotational inertia of the disk , $I=3.8\times 10^{-3}kg.m^{2}$

Torque delivered by the motor , $\tau =17N.m$

Torque is applied for duration , $\Delta t=79ms=0.079s$

(a)

Magnitude of angular momentum of the disk = Angular impulse produced by the torque

$\therefore L=\tau \Delta t=17\times 0.079\frac{kg.m^{2}}{s}$

=> $L=1.343\, \frac{kg.m^{2}}{s}$

Thus angular momentum of disk is $1.343\, \frac{kg.m^{2}}{s}$

(b)

Since Angular momentum , $L=I\omega$

where $\omega$ = Angular velocity of the disk

$=>\omega =\frac{L}{I}=\frac{1.343}{3.8\times 10^{-3}}\frac{rad}{s}$

$\therefore \omega =353\frac{rad}{s}$

Thus angular velocity of the disk is $353\frac{rad}{s}$

5 0

4 years ago

Pendulum takes 1 second to move from x to y so it's frequency equal ​

Pendulum takes 1 second to move from x to y so it's frequency equal