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Free_Kalibri [48]
3 years ago
13

HELPP PLEEEAAAAASSSEEEEWKKKKKKK!!!!!

Physics
2 answers:
nalin [4]3 years ago
8 0
1. make good decisions

2. explosive

3. favorable

answered these on edge. also, you marked this as physics even though its english. might wanna watch out for that lol, so youll get a quicker answer
frutty [35]3 years ago
4 0

Answer:

First one is Make good decisions and second is explosive last One i

Explanation:

Edge

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Derive the equation of motion of the block of mass m1 in terms of its displacement x. The friction between the block and the sur
Alenkasestr [34]

Answer:

the equivalent mass : m_e = m_1+m_2+\frac{I}{R^2}

the equation of the motion of the block of mass m_1 in terms of its displacement is = (m_1+m_2+\frac{I}{R^2} )(\bar x) = (m_2gsin \phi) -(m_1gsin \beta)

Explanation:

Let use m₁ to represent the mass of the block and m₂ to represent the mass of the cylinder

The radius of the cylinder  be = R

The distance between the center of the pulley to center of the block to be = x

Also, the angles of inclinations of the cylinder and the block with respect to the ground to be \phi and \beta respectively.

The velocity of the block to be = v

The equivalent mass of the system = m_e

In the terms of the equivalent mass, the kinetic energy of the system can be written as:

K.E = \frac{1}{2} m_ev^2       --------------- equation (1)

The angular velocity of the cylinder = \omega  :  &

The inertia of the cylinder about its center to be = I

The angular velocity of the cylinder can be written as:

v = \omega R

\omega =\frac{v}{R}

The kinetic energy of the system in terms of individual mass can be written as:

K.E = \frac{1}{2}m_1v^2+\frac{1}{2} m_2v^2+\frac{1}{2}I\omega^2

By replacing \omega with \frac{v}{R} ; we have:

K.E = \frac{1}{2}m_1v^2+\frac{1}{2} m_2v^2+\frac{1}{2}I(\frac{v}{R})^2

K.E = \frac{1}{2}(m_1+ m_2+ \frac{I}{R} )v^2   ------------------ equation (2)

Equating both equation (1) and (2); we have:

m_e = m_1+m_2+\frac{I}{R^2}

Therefore, the equivalent mass : m_e = m_1+m_2+\frac{I}{R^2}    which is read as;

The equivalent mass is equal to the mass of the block plus the mass of the cylinder plus the inertia by  the square of the radius.

The expression for the force acting on equivalent mass due to the block is as follows:

f_{block }=m_1gsin \beta

Also; The expression for the force acting on equivalent mass due to the cylinder is as follows:

f_{cylinder} = m_2gsin \phi

Equating the above both equations; we have the equation of motion of the  equivalent system to be

m_e \bar x = f_{cylinder}-f_{block}

which can be written as follows from the previous derivations

(m_1+m_2+\frac{I}{R^2} )(\bar x) = (m_2gsin \phi) -(m_1gsin \beta)

Finally; the equation of the motion of the block of mass m_1 in terms of its displacement is = (m_1+m_2+\frac{I}{R^2} )(\bar x) = (m_2gsin \phi) -(m_1gsin \beta)

8 0
3 years ago
what is the net force on an object that is experiencing a force of 25 N north, a force of 25 N south, a force of 50 N to the eas
REY [17]

Answer:

5 n

Explanation:

25 and 25 cancel each other out and 50-45 is 5

4 0
3 years ago
A current cannot produce a magnetic field. *<br><br> True or false
GalinKa [24]

Answer:

False

Explanation:

False, as a magnetic field is generated whenever current travels through a conductor.

An electromagnet consists of a coil of wire wrapped around a bar of iron. The coil and iron bar get magnetized when electric current flows through the wire. An electromagnet also has north and south magnetic poles. The magnetic field is strongest at either pole of the magnet.

8 0
3 years ago
suppose both the dog and the girl run at a speed of 2 m/s.Calculate both of there kinetic energies. kinetic energy of dog =
Andre45 [30]

Answer:

78

Explanation:

4 0
3 years ago
Read 2 more answers
The engine of a 2000 kg Mercedes going up Pike’s Peak delivers energy to its drive wheel at the rate 100 kW . Neglecting air res
kykrilka [37]

Answer:

v = 10 m/s

Explanation:

given,

Mass of Mercedes engine = 2000 Kg

Power delivered = 100 kW

angle made with horizontal = 30°

acceleration due to gravity =  10 m/s²

largest speed car can sustain = ?

we know,

Power = Force x velocity

P = F x v

P = mg sinθ x v

P = mg sin 30° x v

P = 0.5 mg  x v

v = \dfrac{100 \times 10^3}{0.5\times 2000 \times 10}

v = 10 m/s

hence, the maximum velocity is equal to v = 10 m/s

8 0
3 years ago
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