I am pretty sure the correct answer is C. Water has large heat capacity meaning it can absorb a lot of energy before changing temperature. That helps the body regulate heat since it can be exposed to different environments and experience small temperature changes.
I hope this helps. Let me know if anything is unclear.
I believe the answer would be B
Answer:
-800 kJ/mol
Explanation:
To solve the problem, we have to express the enthalpy of combustion (ΔHc) in kJ per mole (kJ/mol).
First, we have to calculate the moles of methane (CH₄) there are in 2.50 g of substance. For this, we divide the mass into the molecular weight Mw) of CH₄:
Mw(CH₄) = 12 g/mol C + (1 g/mol H x 4) = 16 g/mol
moles CH₄ = mass CH₄/Mw(CH₄)= 2.50 g/(16 g/mol) = 0.15625 mol CH₄
Now, we divide the heat released into the moles of CH₄ to obtain the enthalpy per mole of CH₄:
ΔHc = heat/mol CH₄ = 125 kJ/(0.15625 mol) = 800 kJ/mol
Therefore, the enthalpy of combustion of methane is -800 kJ/mol (the minus sign indicated that the heat is released).
the pH during the titration of 40.00 mL of 0.1000 M HCl after adding 50 mL of 0.1000 M NaOH is pH = 13.39
NaOH + HCl → NaCl + H2O
40.00 ml 0.5M NaOH solution
mol NaOH = 40 ml / 1000 ml / L * 0.5 mol / L = 0.02 mol NaOH
25 mL 0.1 M HCl
mol HCl = 25 mL / 1000 mL / L * 0.1 mol / L = 0, 0025 mol
This reacts with 0.0025 mol NaOH
[NaOH] = 0.269 M
[OH-] = 0.269 M
pOH = - log 0.269
pOH = 13.43
You titrate with 30 mL 0.100 M HCl
Mol HCl = 30 mL / 1000 mL/L * 0.100 mol /L = 0.003 mol HCl
This will react with 0.003 mol NaOH
Mol unreacted NaOH = 0.02 mol - 0.003 mol = 0.017 mol NaOH in 40mL + 30 mL = 70 mL solution
Molarity of NaOH solution = 0.017 mol / 70 mL * 1000 mL/L = 0.243 M
[OH-] = 0.243 M
pOH = - log 0.243
pOH = 0.61
pH = 13.39
40 mL
Titration is defined as "the process of determining the amount of substance A by adding a measured amount of substance B, which is a titrator that reacts until an accurate chemical equivalence point is reached."
Learn more about titration here: brainly.com/question/186765
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