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mart [117]
3 years ago
10

John performs an experiment on an electric circuit. He increases the voltage from 25 volts to 50 volts while keeping the resista

nce constant. What will be the effect of John's changes on the current?
Physics
1 answer:
Marta_Voda [28]3 years ago
6 0

The current will double

Explanation:

The relationship between voltage and current in an electric circuit is given by the following equation (Ohm's law):

V=IR

where

V is the voltage

I is the current

R is the resistance

making R the subject,

R=\frac{V}{I}

Since in this experiment the resistance is kept constant, we can write:

\frac{V_1}{I_1}=\frac{V_2}{I_2}

where

V_1=25 V is the voltage in the 1st experiment

V_2=50 V is the voltage in the 2nd experiment

I_1,I_2 are the currents in the 1st and 2nd experiment

We can re-arrange the equation as

\frac{I_2}{I_1}=\frac{V_2}{V_1}=\frac{50}{25}=2

This means that the current will double in the 2nd experiment.

Learn more about current and voltage:

brainly.com/question/4438943

brainly.com/question/10597501

brainly.com/question/12246020

#LearnwithBrainly

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Tarzan, who weighs 825 N, swings from a cliff at the end of a 19.7 m vine that hangs from a high tree limb and initially makes a
kodGreya [7K]

Answer:

a) T = (281.47 i ^ + 714.56 j ^) N , b) F_net = (281.47 i ^ - 110.44 j ^) N ,

c)  F = 281.70 N, d)    θ = 338.58º , e)  a = 3,588 m / s² , f)  θ = 201.45º

Explanation:

For this exercise we will use Newton's second law on each axis

X axis

         -Tₓ = m aₓ

Y Axisy

          T_{y} –W = m a_{y}

Let's use trigonometry to find the components of force

          sin 21.5 = Tₓ / T

          cos 21.5 = T_{y} / T

          Tₓ = T sin 21.5

          T_{y} = T cos 21.5

          Tₓ = 768 sin 21.5 = 281.47 N

          T_{y} = 768 cos 21.5 = 714.56 N

a) the force of the rope on Tarzan is

          T = (281.47 i ^ + 714.56 j ^) N

b) The net force is the subtraction of the tension minus the weight of Tarzan

Y  Axis   F_net = 714.56 - 825 = -110.44 N

              F_net = (281.47 i ^ - 110.44 j ^) N

c) Let's use Pythagoras' theorem

      F = √ (Fₓ² + T_{y}²)

      F = √ (281.47² + 110.44²)

      F = 281.70 N

d) Let's use trigonometry

     tan θ = F_{y} / Fₓ

      θ = tan⁻¹ F_{y} / Fₓ

      θ = tan⁻¹ (-110.44 / 281.47)

       θ = -21.42º

This angle is average clockwise, for counterclockwise measurement

       θ = 360 - 21.42

       θ = 338.58º

Acceleration

X axis

             Tₓ = m aₓ

             aₓ = Tₓ / m

The mass of Tarzan is

             m = W / g

             m = 825 / 9.8 = 84.18 kg

             

             aₓ = 281.47 / 84.18

             aₓ = -3.34 m / s2

Y Axis

            T_{y}-W = m a_{y}

            a_{y} = (T_{y} -W) / m

            a_{y} = (714.56-825) / 84.18

            a_{y} = - 1,312 m / s²

Acceleration Module

             a = √ aₓ² + a_{y}²

             a = √ (3.34² +1.312²)

             a = 3,588 m / s²

The angle

          θ = tan⁻¹ a_{y} / aₓ

          θ = tan⁻¹ (-1312 / -3.34)

          θ = 21.45º

Notice that the two components of the acceleration are negative, so the angle is in the third quadrant, to measure from the x-axis

          θ = 180 + 21.45

          θ = 201.45º

3 0
3 years ago
What is electrical energy ?
fredd [130]

Explanation:

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HOPE THIS HELPS YOU

6 0
3 years ago
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liraira [26]

Answer:

(a) work done by Jack is -2200J

(b) work done by Jill is 0

Explanation:

Given;

Initially boat's position =  < 2, 0, 3 > m

Final boat's position = < 6, 0, 1 > m

change in position = < 4, 0, -2 >

Force exerted by Jack =  < -440, 0, 220 > N

Force exerted by Jill = < 170, 0, 340 > N

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work done = force x distance

Jack's work = < -440, 0, 220 > N x < 4, 0, -2 > m

                    = [(-440*4) + (0*0) + (220*-2)]

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Part (b) How much work does Jill do?

Jill's work = < 170, 0, 340 > N x < 4, 0, -2> m

                 = [(170*4) + (0*0) + (340*-2)]

                  = 680 J - 680 J

                   = 0

7 0
4 years ago
What is the effect that distance has on gravity?
IgorLugansk [536]
The forces of gravity between two objects are smaller when the objects are farther apart.
3 0
3 years ago
Give an example of an object that has balanced forces acting on it.
Gnesinka [82]
If the forces on an object are balanced (or if there are no forces acting on it), this is what happens:

a stationary object stays still
a moving object continues to move at the same speed and in the same direction
4 0
3 years ago
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