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Fittoniya [83]
4 years ago
10

Please HELP!

Chemistry
1 answer:
abruzzese [7]4 years ago
8 0

This would be difficult to specify for you because you did not provide the genotype of the other parent. However, there are limitations to the possible combinations, so I will do each to help you out.

<u>1st possibility:</u>

    <u>B      B</u>

B  BB  BB

b  Bb   Bb

Brown eyes: 4 out of 4 or 100%

Blue eyes:    0 out of 4 or 0%.

<u>2nd possibility:</u>

    <u>B      b</u>

B  BB  Bb

b  Bb   bb

Brown eyes: 3 out of 4 or 75%

Blue eyes:    1 out of 4 or 25%.

<u>3rd possibility:</u>

    <u>b      b</u>

B  Bb  Bb

b  bb   bb

Brown eyes: 2 out of 4 or 50%

Blue eyes:    2 out of 4 or 50%.

<u>As long as there is a capital letter in the genotype, the dominant trait will come out. So if the combination is </u><u>Bb or BB</u><u>, then </u><u>BROWN </u><u>in this case will come out. The only time </u><u>BLUE eyes </u><u>will come out is if has two recessives in its genotype or </u><u>bb.</u>

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As there are more O₂ moles than required (7.81 vs 5.51), O₂ is the reactant in excess. That means that <em>C₆H₁₄ is the limiting reactant</em>.

Now we can <u>calculate how much water can be formed</u>, using <em>the number of moles of the limiting reactant</em>:

  • 0.58 mol C₆H₁₄ * \frac{14molH_2O}{2molC_6H_{14}} = 4.06 mol H₂O
5 0
3 years ago
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Explanation:

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