<h3>
Answer:</h3>
The pressure increases by 10% of the original pressure
Thus the new pressure is 1.1 times the original pressure.
<h3>
Explanation:</h3>
We are given;
- Initial temperature as 30°C, but K = °C + 273.15
- Thus, Initial temperature, T1 =303.15 K
- Final temperature, T2 is 333.15 K
We are required to state what happens to the pressure;
- We are going to base our arguments to Pressure law;
- According to pressure law, the pressure of a gas and its temperature are directly proportional at a constant volume
- That is; P α T
- Therefore, at varying pressure and temperature
Assuming the initial pressure, P1 is P
Rearranging the formula;
[tex]P2=\frac{P1T2}{T1}[/tex]
= 1.10 P
The new pressure becomes 1.10P
This means the pressure has increased by 10%
We can conclude that, the new pressure will be 1.1 times the original pressure.
Answer:
c) more OH⁻ ions than H₃O⁺ ions
Explanation:
A substance with a PH of 9 implies that it has more OH⁻ ions than H₃O⁺ ions.
Such substances are said to be an alkaline or a base.
A base is a substance the produces excess hydroxyl ion in aqueous solutions.
An acid will produce excess hydroxonium ions in a solution.
So, the pH scale is used to indicate whether a substance is an acid or base or non of them.
Acids have pH of less than 7
Bases have pH of > 7
Write procedural steps that allow you to demonstrate the sun's role in the water cycle using common material - for each explain what you are modeling and how the materials you have chosen represent nature.
Using the accepted value for the volume of 1 gram of water at the temperature of the room that you reported above, what is the accepted value for the density of water
Answer:
your answer would be the last one gold
Answer:
Keq =1.50108
Explanation:
The given reactionis
C₂H₂(g) +2H₂(g) -------------> C₂H₂(g)
ΔG0 f=ΔG0f n (products) - ΔG0f n (reactants )
= -32.89 kJ/mol - (209.2 kJ/mol+2*0.0 kJ/mol)
= - 242.09kJ/mol
ΔG= -RTlnKeq
ln Keq = -ΔG/RT
=-(- 242.09kJ/mol ) / 2 k cal /mol*298 K
=0.406
Keq =e0.406
Keq =1.50108
