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Zarrin [17]
3 years ago
5

We bored Meeting id:333-065-2087 Password:5FRgXJ

Chemistry
2 answers:
MAXImum [283]3 years ago
7 0
BET
I'll join never.
Stop posting stuff other than questions.
Juli2301 [7.4K]3 years ago
4 0

Answer:

pls don't post irrelevant questions

Explanation:

FOLLOW MY ACCOUNT PLS PLS

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Pure ethylene glycol, , is added to 2.00 kg of water in the cooling system of a car. The vapor pressure of the water in the syst
spayn [35]

Answer:

1367.7 g of ethylene glycol was added to the solution

Explanation:

In order to find out the mass of glycol we added, we apply the colligative property of lowering vapor pressure: ΔP = P° . Xm

ΔP = Vapor pressure of pure solvent (P°) - Vapor pressure of solution(P')

525.8 mmHg - 451 mmHg = 451 mmHg . Xm

74.8 mmHg / 451 mmHg = Xm → 0.166 (mole fraction of solute)

Xm = Mole fraction of solute / Moles of solute + Moles of solvent

We can determine the moles of solvent → 2000 g . 1  mol/18 g = 111.1 mol

(Notice we converted the 2kg of water to g)

0.166 = Moles of solute / Moles of solute + 111.1 moles of solvent

0.166 (Moles of solute + 111.1 moles of solvent) = Moles of solute

18.4 moles = Moles of solute - 0.166 moles of solute

18.4 = 0.834 moles of solute → Moles of solute = 18.4/0.834 = 22.06 moles

Let's convert the moles to mass → 62 g/mol . 22.06 mol = 1367.7 g

6 0
3 years ago
What is the molarity of a 799 mL solution that contains 3.3 moles of NaNO3?
rusak2 [61]

Answer:   I think It might be 1 M???

Explanation:  Sorry I'm not in high school I put the wrong age

8 0
3 years ago
Dry air (0% humidity) is approximately 78% N2, 21% O2, and 1% Ar by moles. Calculate the molar mass and density of dry air at 0
ser-zykov [4K]
Shdhdhdhdhdhshshhzshshshdhdhshd
7 0
3 years ago
HURRY! 10 POINTS!!
frosja888 [35]

Answer:

Weak bonds require less energy to form than strong bonds

Explanation:

According to Coulomb's law, the force between two species is inversely proportional to the distance between them. That said, the bigger the atoms are, the greater the bond length should be to form a molecule.

As a result, for a greater bond length, the attraction force is lower than for a shorter bond length. This implies that large atoms would form weak bonds and small atoms would form strong bonds.

Bond energy is defined as the amount of energy required to break the bond. If a bond is weak, it would require a low amount of energy to break it. This is also true for energy of formation, as it's the same process taking place in the opposite direction.

6 0
4 years ago
Calculate the volume of a sample of iron that has a density of 6.8 g/mL and a mass of 6780 mg.
Veronika [31]

Answer:

m= 6780mg = 6.78g = 6.8g

d= 6.8g/ml

V= m/d

V= 1ml

8 0
3 years ago
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