Three consecutive integers have a sum of 45
2 answers:
Three consecutive integers that have a sum of 45 are 14, 15 and 16. 14+15+16=45
14 + 15 + 16
13 + 14 + 18
12 + 13 + 20
11 + 12 + 22
10 + 11 + 24
9 + 10 + 26
8 + 9 + 28
7 + 8 + 30
6 + 7 + 32
5 + 6 + 34
4 + 5 + 36
3 + 4 + 38
2 + 3 + 40
1 + 2 + 42
0 + 1 + 44
0 + 0 + 45
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Answer:
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Answer:
21
Step-by-step explanation:
Old A: 6 New A: 9
Multiply 6 by 1.5 to get 9.
Therefore multiply 14 by 1.5 as well, which gives you 21.
