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Harman [31]
3 years ago
6

Harry wants to buy some ice cream for his friends and himself. At the ice cream parlor, one ice cream costs $3.99. Which express

ion below could you use to compute the cost of 4 ice creams?
Mathematics
2 answers:
borishaifa [10]3 years ago
5 0
4 x $3.99 = $15.96
Hope this helps and have a great day! :)
satela [25.4K]3 years ago
4 0
4 multiplied by 3.99 will = your answer....Please mark brainliest...
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Which figure is not a parallelogram?
lara31 [8.8K]

Answer:

the second one

Step-by-step explanation:

it does not say that both sides are parallel

3 0
3 years ago
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7. Is a triangle with side lengths 9, 18, 7 a right triangle, an acute triangle, or
Reptile [31]
I think the answer is Obtuse
8 0
3 years ago
Solve the system with elimination 4x+3y=1 -3x-6y=3
Nuetrik [128]

Answer:

x = 1, y = -1

Step-by-step explanation:

If we have the two equations:

4x+3y=1 and -3x - 6y = 3, we can look at which variable will be easiest to eliminate.

y looks like it might be easy to get rid of, we just have to multiply 4x+3y=1  by 2 and y is gone (as -6y + 6y = 0).

So let's multiply the equation 4x+3y=1  by 2.

2(4x + 3y = 1)\\8x + 6y = 2

Now we can add these equations

8x + 6y = 2\\-3x-6y=3\\

------------------------

5x = 5

Dividing both sides by 5, we get x = 1.

Now we can substitute x into an equation to find y.

4(1) + 3y = 1\\4 + 3y = 1\\3y = -3\\y = -1

Hope this helped!

5 0
3 years ago
Help out?? Mathematics image.
Brilliant_brown [7]

Answer: (12) ∠1 = 20° (13) ∠2 = 50° (14) ∠3 = 15° (15) UV = 80° (16) AB = 40°  (17) ABC <em>or</em>  180° - CD (18) BC - 140°  (19) ABC = 150°

<u>Step-by-step explanation:</u>

12) \frac{1}{2}(UV - ST) = ∠1

\frac{1}{2}(80 - 40) = ∠1

\frac{1}{2}(40) = ∠1

20 = ∠1

13) \frac{1}{2}(UV + ST) = ∠2

\frac{1}{2}(70 + 30) = ∠2

\frac{1}{2}(100) = ∠2

50 = ∠2

14) \frac{1}{2}(VB - BS) = ∠3

\frac{1}{2}(60 - 30) = ∠3

\frac{1}{2}(30) = ∠3

15 = ∠3

15) \frac{1}{2}(UV - ST) = ∠1

\frac{1}{2}(UV - 20) = 30

UV - 20 = 60

UV = 80

16) ∠1 = arc AB

     ∠1 = 40

              arc AB = 40

17) arc AB + arc BC = arc AC

                               = 180 = arc CD  

18) ∠1 + ∠2 + ∠3 = 180

   20 + ∠2  + 20 = 180

            ∠2 + 40 = 180

                      ∠2  = 140

19) ∠1 + ∠ 2 = arc ABC

     ∠1 + ∠2 + ∠3 = 180

    arc ABC + 30 = 180

            arc ABC = 150


4 0
3 years ago
Solve the following equation by factoring:9x^2-3x-2=0
olya-2409 [2.1K]

Answer:

The two roots of the quadratic equation are

x_1= - \frac{1}{3} \text{ and } x_2= \frac{2}{3}

Step-by-step explanation:

Original quadratic equation is 9x^{2}-3x-2=0

Divide both sides by 9:

x^{2} - \frac{x}{3} - \frac{2}{9}=0

Add \frac{2}{9} to both sides to get rid of the constant on the LHS

x^{2} - \frac{x}{3} - \frac{2}{9}+\frac{2}{9}=\frac{2}{9}  ==> x^{2} - \frac{x}{3}=\frac{2}{9}

Add \frac{1}{36}  to both sides

x^{2} - \frac{x}{3}+\frac{1}{36}=\frac{2}{9} +\frac{1}{36}

This simplifies to

x^{2} - \frac{x}{3}+\frac{1}{36}=\frac{1}{4}

Noting that (a + b)² = a² + 2ab + b²

If we set a = x and b = \frac{1}{6}\right) we can see that

\left(x - \frac{1}{6}\right)^2 = x^2 - 2.x. (-\frac{1}{6}) + \frac{1}{36} = x^{2} - \frac{x}{3}+\frac{1}{36}

So

\left(x - \frac{1}{6}\right)^2=\frac{1}{4}

Taking square roots on both sides

\left(x - \frac{1}{6}\right)^2= \pm\frac{1}{4}

So the two roots or solutions of the equation are

x - \frac{1}{6}=-\sqrt{\frac{1}{4}}  and x - \frac{1}{6}=\sqrt{\frac{1}{4}}

\sqrt{\frac{1}{4}} = \frac{1}{2}

So the two roots are

x_1=\frac{1}{6} - \frac{1}{2} = -\frac{1}{3}

and

x_2=\frac{1}{6} + \frac{1}{2} = \frac{2}{3}

7 0
1 year ago
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