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2 years ago

Which line represents a stationary object.

Chemistry

2 answers:

Lina20 [59]2 years ago

8 0

Answer:

Green line

Explanation:

Whenever the position of the object does not change with respect to time, then object said to be at rest. The rest stare is also known as stationary condition.

Here, the position of object changes in all the graphs except the green line.

So, the graph which is represented by the green line is said to be at stationary position.

For stationary position, the time increases but the position remains same. It means the graph is a straight line parallel to time axis.

tiny-mole [99]2 years ago

7 0

The green one cause its staying in the same position even when time is passing. - hope this helped have a great day

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Give five examples of structures with this formula (c6h12). at least one should contain a ring, and at least one should contain

hammer [34]

Answer: -

Following are five examples of structures with the chemical formula C₆H₁₂

Compound A is Hexene.

Compound B is 2-Hexene.

Compound C is 3-Hexene.

Compound D is Cyclohexane.

Compound E is Methylcyclopentane.

As we can see Hexene, 2- Hexene and 3-Hexene all have double bonds.

Cyclohexane and Methylcyclopentane contains a ring.

7 0

3 years ago

Determine the pH of a 2.8 ×10−4 M solution<br> of Ca(OH)2.

shepuryov [24]

Answer:

pH = 10.75

Explanation:

To solve this problem, we must find the molarity of [OH⁻]. With the molarity we can find the pOH = -log[OH⁻]

Using the equation:

pH = 14 - pOH

We can find the pH of the solution.

The molarity of Ca(OH)₂ is 2.8x10⁻⁴M, as there are 2 moles of OH⁻ in 1 mole of Ca(OH)₂, the molarity of [OH⁻] is 2*2.8x10⁻⁴M = 5.6x10⁻⁴M

pOH is

pOH = -log 5.6x10⁻⁴M

pOH = 3.25

pH = 14-pOH

3 0

3 years ago

The formation constant for the reaction ag (aq) 2nh3(aq) ag(nh3)2 (aq) is kf = 1.7 × 107 at 25°c. what is δg° at this temperatur

anzhelika [568]

The value of ΔG° at this temperature is -18034.18 J/mol

Calculation,

Given information

formation constant (Kf)= 1.7 × $10^{7}$

Universal gas constant (R) = 8.314 J/K• mol

Temperature = 25° C = 25 °C + 273 = 300 K

Formula used:

ΔG° = -RT㏑Kf

By putting the valur of R,T, Kf we get the value of ΔG°

ΔG° = - 8.314 J/K• mol×300K㏑ 1.7 × $10^{7}$

ΔG° = -2494.2㏑ 1.7 × $10^{7}$ = -18034.18 J/mol

So, change in standard Gibbs's free energy is -18034.18 J/mol

Learn about formation constant

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1 year ago

Is making ice cream a physical or chemical change

harina [27]

Answer:

Physical change

Explanation:

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3 years ago

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Aneli [31]

Dihydrogen oxide is the right answer. Dihydrogen oxide is just 2 hydrogen and 1 oxygen which is H2O or water.

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2 years ago