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exis [7]
3 years ago
11

Which line represents a stationary object.

Chemistry
2 answers:
Lina20 [59]3 years ago
8 0

Answer:

Green line

Explanation:

Whenever the position of the object does not change with respect to time, then object said to be at rest. The rest stare is also known as stationary condition.

Here, the position of object changes in all the graphs except the green line.

So, the graph which is represented by the green line is said to be at stationary position.

For stationary position, the time increases but the position remains same. It means the graph is a straight line parallel to time axis.

tiny-mole [99]3 years ago
7 0

The green one cause its staying in the same position even when time is passing. - hope this helped have a great day

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An ideal gas contained in a piston-cylinder assembly is compressed isothermally in an internally reversible process.
Tju [1.3M]

Answer:

a) \Delta S

b) entropy of the sistem equal to a), entropy of the universe grater than a).

Explanation:

a) The change of entropy for a reversible process:

\delta S=\frac{\delta Q}{T}

\Delta S=\frac{Q}{T}

The energy balance:

\delta U=[tex]\delta Q- \delta W

If the process is isothermical the U doesn't change:

0=[tex]\delta Q- \delta W

\delta Q= \delta W

Q= W

The work:

W=\int_{V1}^{V2}P*dV

If it is an ideal gas:

P=\frac{n*R*T}{V}

W=\int_{V1}^{V2}\frac{n*R*T}{V}*dV

Solving:

W=n*R*T*ln(V2/V1)

Replacing:

\Delta S=\frac{n*R*T*ln(V2/V1)}{T}

\Delta S=n*R*ln(V2/V1)}

Given that it's a compression: V2<V1 and ln(V2/V1)<0. So:

\Delta S

b) The entropy change of the sistem will be equal to the calculated in a), but the change of entropy of the universe will be 0 in a) (reversible process) and in b) has to be positive given that it is an irreversible process.

7 0
3 years ago
Calculate the molarity of 22.5 g of MgS in 829 mL of solution
krek1111 [17]

Answer:18652.5

Explanation

5 0
3 years ago
Which of the following has no electrons? Use a periodic table. Question 1 options: H He H– He 2+ Save
Elodia [21]

An electron is a negatively charged subatomic particle present in the space outside the nucleus of an atom. The loss of electron from an atom results in the formation of cation whereas gaining of electron by an atom results in the formation of anion. The cation possesses positive charge due to loss of electron and anion possesses negative charge due to gain of electron.

The neutral atom has no charge on it.

For given atomic symbols:

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The atomic number of hydrogen is 1 and the given symbol has no charge that means it is in its neutral state. So, the number of electrons in H is 1.

  • He

The atomic number of helium is 2 and the given symbol has no charge that means it is in its neutral state. So, the number of electrons in He is 2.

  • H^{-}

The atomic number of hydrogen is 1 and the given symbol has a negative charge that represents a gain of electron. So, the number of electrons in H^{-} is 2.

  • He^{2+}

The atomic number of helium is 2 and the given symbol has two positive charge that represents loss of two electrons. So, the number of electrons in He^{2+} is 0.

Hence, He^{2+} has no electrons.

6 0
3 years ago
A student finds that the water's temperature went from 18oC to 38oC. Calculate how many calories are in the peanut.
Norma-Jean [14]

Answer:

567 calories.

Explanation:

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What is the product for MgBr2+ Cl2
nikklg [1K]

???...........…..............

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