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exis [7]
3 years ago
11

Which line represents a stationary object.

Chemistry
2 answers:
Lina20 [59]3 years ago
8 0

Answer:

Green line

Explanation:

Whenever the position of the object does not change with respect to time, then object said to be at rest. The rest stare is also known as stationary condition.

Here, the position of object changes in all the graphs except the green line.

So, the graph which is represented by the green line is said to be at stationary position.

For stationary position, the time increases but the position remains same. It means the graph is a straight line parallel to time axis.

tiny-mole [99]3 years ago
7 0

The green one cause its staying in the same position even when time is passing. - hope this helped have a great day

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Calculate the pH of: (a) 0.1M HCl; (b) 0.1M NaOH; (c) 3 X 10% M HNO3; (d) 5 X 10-10 M HCIO.; and (e) 2 x 10-8 M KOH.
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Answer:

(a) pH = -Log (0.1M) = 1

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Explanation:

To calculate de pH of an acid solution the formula is:

pH = -Log ([H^{+}]) = 1

were [H^{+}] is the concentration of protons of the solution. Therefore it is necessary to know the concentration of the protons for every solution in order to solve the problem.

(a) and (c) are strong acids so they dissociate completely in aqueous solution. Thus, the concentration of the acid is the same as the protons.

(b) and (e) are strong bases so they dissociate completely in aqueous solution too. Thus, the concentration of the base is the same as the oxydriles. But in this case it is necessary to consider the water autoionization to calculate the protons concentration:

K_{w} =[H^{+} ][OH^{-}]=10^{-14}

clearing the [H^{+} ]

[H^{+} ]=\frac{10^{-14}}{[OH^{-}]}

(d) is a weak base so it is necessary to solve the equilibrium first, knowing Ka=3.24x10^{-8}

The reaction is HClO  →  H^{+} + CO^{-} so the equilibrium is

Ka=3.24x10^{-8}=\frac{x^{2}}{5x10^{-8}-x}

clearing the <em>x</em>

{x^{2}={1.62x10^{-17}-3.24x10^{-8}x}

x=[H^{+}]=4.93x10^{-10}

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Explanation:

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