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stira [4]
4 years ago
14

Who granted the first charter to Louisiana? History plz help need question asap will make brainliest

Chemistry
1 answer:
Sveta_85 [38]4 years ago
6 0

ANSWER: Louisiana State Lottery Company ran the Louisiana Lottery in the mid 19th century. The company was chartered on August 11, 1868 by the Louisiana General Assembly with a 25-year charter and in exchange gave the State $40,000 a year. In December 1893, the charter expired as all lottery operations were banned by Murphy Foster.

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Answer:

2. reasoning

Explanation:

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3 years ago
Which statements describes Newton's law of universal gravitation ?
IrinaK [193]

Your answer is D. You're Welcome

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Consider the following chemical reaction: 2KCl + 3O2 --> 2KClO3. If you are given 100.0 moles of KCl and 100.0 moles of O2...
g100num [7]

Answer:

O₂; KCl; 33.3  

Explanation:

We are given the moles of two reactants, so this is a limiting reactant problem.

We know that we will need moles, so, lets assemble all the data in one place.

            2KCl  +  3O₂ ⟶ 2KClO₃

n/mol:  100.0   100.0

1. Identify the limiting reactant

(a) Calculate the moles of KClO₃ that can be formed from each reactant

(i)From KCl

\text{Moles of KClO}_{3} = \text{100.0 mol KCl} \times \dfrac{\text{2 mol KClO}_{3}}{\text{2 mol KCl}} = \text{100.0 mol KClO}_{3}

(ii) From O₂

\text{Moles of KClO}_{3} = \text{100.0 mol O}_{2} \times \dfrac{\text{2 mol KClO}_{3}}{\text{3 mol O}_{2}} = \text{66.67 mol KClO}_{3}

O₂ is the limiting reactant, because it forms fewer moles of the KClO₃.

KClO₃ is the excess reactant.

2. Moles of KCl left over

(a) Moles of KCl used

\text{Moles used} = \text{100.0 mol O}_{2} \times \dfrac{\text{2 mol KCl}}{\text{3 mol O}_{2}} = \text{66.67 mol KCl}

(b) Moles of KCl left over

n = 100.0 mol - 66.67 mol = 33.3 mol

3 0
3 years ago
What volume in litres will 38gr of F2 occupy at 0.999 bar and 273 K
FrozenT [24]

Answer:

V=22.68L

Explanation:

Hello,

In this case, we use the ideal gas equation to compute the volume as shown below:

PV=nRT\\\\V=\frac{nRT}{P}

Nonetheless we are given mass, for that reason we must compute the moles of gaseous fluorine (molar mass: 38 g/mol) as shown below:

n=38 g *\frac{x}{y}  \frac{1mol}{38 g} =1mol

Thus, we compute the volume with the proper ideal gas constant, R:

V=\frac{1mol*0.083\frac{bar*L}{mol*K}*273K}{0.999bar} \\\\V=22.68L

Best regards.

7 0
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All I know us the San Andreas fault line. That earthquake is far overdo
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