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3 years ago

In which situation are unbalanced forces acting on an object?(1 point)

Chemistry

1 answer:

Alex Ar [27]3 years ago

7 0

Answer:

1. Two people stand on the same side of a large tire. Both people pull the tire with equal force.

2. an object’s ability to not change its motion

3. The car moves forward, while inertia keeps the balloon in place.

4. The unbalanced forces of air resistance and gravity slow the airplane and pull it down.

5. The force acting on the object must be unbalanced.

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nignag [31]

Organic chemistry as the the study of general properties and compositions of organic compounds.

<h3 />

<h3>What is organic chemistry?</h3>

Organic chemistry can be simply defined as the study of organic compounds.

Organic chemistry studies the structure, properties, composition, reactions, and preparation of carbon-containing compounds also known as organic compounds.

Thus, we can defined organic chemistry as the the study of general properties and compositions of organic compounds.

Learn more about organic chemistry here: brainly.com/question/704297

6 0

2 years ago

Read 2 more answers

Consider the following reaction between mercury(II) chloride and oxalate ion.

Alina [70]

<u>Answer:</u> The rate law of the reaction is $\text{Rate}=k[HgCl_2][C_2O_4^{2-}]^2$

<u>Explanation:</u>

Rate law is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.

For the given chemical equation:

$2 HgCl_2(aq.)+C_2O_4^{2-}(aq.)\rightarrow 2Cl^-(aq.)+2CO_2(g)+Hg_2Cl_2(s)$

Rate law expression for the reaction:

$\text{Rate}=k[HgCl_2]^a[C_2O_4^{2-}]^b$

where,

a = order with respect to $HgCl_2$

b = order with respect to $C_2O_4^{2-}$

Expression for rate law for first observation:

$3.2\times 10^{-5}=k(0.164)^a(0.15)^b$ ....(1)

Expression for rate law for second observation:

$2.9\times 10^{-4}=k(0.164)^a(0.45)^b$ ....(2)

Expression for rate law for third observation:

$1.4\times 10^{-4}=k(0.082)^a(0.45)^b$ ....(3)

Expression for rate law for fourth observation:

$4.8\times 10^{-5}=k(0.246)^a(0.15)^b$ ....(4)

Dividing 2 from 1, we get:

$\frac{2.9\times 10^{-4}}{3.2\times 10^{-5}}=\frac{(0.164)^a(0.45)^b}{(0.164)^a(0.15)^b}\\\\9=3^b\\b=2$

Dividing 2 from 3, we get:

$\frac{2.9\times 10^{-4}}{1.4\times 10^{-4}}=\frac{(0.164)^a(0.45)^b}{(0.082)^a(0.45)^b}\\\\2=2^a\\a=1$

Thus, the rate law becomes:

$\text{Rate}=k[HgCl_2]^1[C_2O_4^{2-}]^2$

3 0

3 years ago

Pls I need help with these ques. help plsssssssssssssss

snow_lady [41]

Answer:

q1..no.2 and 4 are aromatic

6 0

3 years ago

What makes organic compounds reactive?

konstantin123 [22]

Answer:

The functional groups

Explanation:

An organic compound is a compound that contain carbon and another element such as hydrogen, oxygen, nitrogen, etc.
Functional groups are the portions of an organic compound that is capable of characteristic reactions.
Functional groups determine the chemical and physical properties of many organic compounds.

3 0

3 years ago

A membrane Is a flexible outer layer found on:

ratelena [41]

Answeridk:

Explanation:isk

8 0

3 years ago