Question

You are standing on the sidewalk, waiting to cross Michigan Street. A Toyota RAV4 (~2500 lbs) goes by at 30 MPH. Assuming you are about 20 feet from the center of the lane, what is the angular momentum of the RAV4 about your position?

Answer 1

Answer:

$9.27\times 10^{4} Kg.m^{2}/s$

Explanation:

Angular momentum is given by mvr where m is mass of the car, v is the speed of the car and r is the distance from the centre of the lane.

In this case, mass is 2500 lbs which to convert to Kg we multiply by 0.453592 hence 2500*0.453592=1133.98

Also, the speed we convert from mph to m/s by multiplying by 0.44704 hence 30*0.44704=13.4112 m/s

Finally, the distance given in ft is converted to m by multiplying it by 0.3048

The angular momentum will then be $1133.98*13.4112*20*0.3048\approx 9.27\times 10^{4} Kg.m^{2}/s$