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ValentinkaMS [17]
3 years ago
11

You are standing on the sidewalk, waiting to cross Michigan Street. A Toyota RAV4 (~2500 lbs) goes by at 30 MPH. Assuming you ar

e about 20 feet from the center of the lane, what is the angular momentum of the RAV4 about your position?
Physics
1 answer:
Montano1993 [528]3 years ago
6 0

Answer:

9.27\times 10^{4} Kg.m^{2}/s

Explanation:

Angular momentum is given by mvr where m is mass of the car, v is the speed of the car and r is the distance from the centre of the lane.

In this case, mass is 2500 lbs which to convert to Kg we multiply by 0.453592 hence 2500*0.453592=1133.98

Also, the speed we convert from mph to m/s by multiplying by 0.44704 hence 30*0.44704=13.4112 m/s

Finally, the distance given in ft is converted to m by multiplying it by 0.3048

The angular momentum will then be 1133.98*13.4112*20*0.3048\approx 9.27\times 10^{4} Kg.m^{2}/s

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