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3 years ago

13

A 3-kg block, attached to a spring, executes simple harmonic motion according to x= 2cos(50t) where x is in meters and t is in s

econds. The spring constant of the spring is: (a) 1 N/m (b) 100 N/m (c) 150 N/m (d) 7500 N/m (e) none of the above

1 answer:

saw5 [17]3 years ago

4 0

Explanation:

w=50=√k/m=√k/3

SO

(50²)*3 is 7500N/m

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umka21 [38]

Answer:

Part a)

$a = 3.68 m/s^2$

Part b)

$a = 11.8 m/s^2$

Explanation:

Part a)

For force conditions of two blocks we will have

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now from above equations we have

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now we know that

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$m_2 = \frac{412}{9.8} = 42 kg$

now from above equation we have

$a = \frac{92.65 - 42}{92.65 + 42}(9.8)$

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Part b)

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3 years ago