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Annette [7]
3 years ago
13

An electroscope is a simple device consisting of a metal ball that is attached by a conductor to two thin leaves of metal foil p

rotected from air disturbance in a jar. When the ball is touched by a charged body, why do the leaves that normally hang straight down spread apart?
1. None of these
2. The charge transfers to the leaves through the metal ball. Since the leaves have the same charge, they are pushed away from each other.
3. The charge transfers to the leaves through the glass. Since the leaves have different charges, they are pushed away from each other.
4. The charge transfers to the leaves through the metal ball. Since the leaves have different charges, they are pushed away from each other.
5. The charge transfers to the two leaves through the glass. Since the leaves have the same charges, they are pushed away from each other
Physics
1 answer:
AlexFokin [52]3 years ago
4 0

Answer:

2. The charge transfers to the leaves through the metal ball. Since the leaves have the same charge, they are pushed away from each other.

Explanation:

As we know that two similar charges always repel each other and two opposite charges always attracts each other

So here we know that when a charged body is in contact with the metal ball then we know that metal is good conductor so through this metal ball charge is transferred to the the thin metal plates

Now this metal plate will separate by mutual repulsion force on them and they moved apart

So correct answer will be

2. The charge transfers to the leaves through the metal ball. Since the leaves have the same charge, they are pushed away from each other.

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A solenoid of length 0.700 m having a circular cross-section of radius 5.00 cm stores 6.00 µJ of energy when a 0.400-A current r
Alborosie

Answer:

104

Explanation:

U = Energy stored in the solenoid = 6.00 μJ = 6.00 x 10⁻⁶ J

i = current flowing through the solenoid = 0.4 A

L = inductance of the solenoid

Energy stored in the solenoid is given as

U = (0.5) L i²

6.00 x 10⁻⁶ = (0.5) L (0.4)²

L = 75 x 10⁻⁶

Inductance is given as

l = length of the solenoid = 0.7 m

N = number of turns

r = radius = 5.00 cm = 0.05 m

Area of cross-section is given as

A = πr²

A = (3.14) (0.05)²

A = 0.00785 m²

Inductance is given as

L=\frac{\mu _{o}N^{2}A}{l}

75\times 10^{-6}=\frac{(12.56\times 10^{-7})N^{2}(0.00785)}{0.7}

N = 73

Winding density is given as

density = n = \frac{N}{l}

n = \frac{73}{0.7}

n = 104

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Answer:

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Explanation:

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Like this:

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2).  Calculate how long it takes an object dropped from rest to fall 42.3 m.  Use the "dropped from rest" formula:

Distance = (1/2) (acceleration) (time)²

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I wish I could make it more complicated for you, but I don't know how.

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