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2 years ago

How can acceleration be described?

Physics

2 answers:

krek1111 [17]2 years ago

7 0

Answer:

The definition of acceleration is: Acceleration is a vector quantity that is defined as the rate at which an object changes its velocity. An object is accelerating if it is changing its velocity.

Explanation:

ivanzaharov [21]2 years ago

5 0

Answer:

A vehicle's capacity to gain speed within a short time.

Explanation:

Hope that helps you :)

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For the circuit in the previous part, what happens to the maximum current if the frequency is doubled and the inductance is halv

tamaranim1 [39]

Answer:

Following are the responses to these question:

Explanation:

Since the $max^{m}$ is the current of ckt which depend on the reactance which inductor that also enables the ckt and inductor resistance $(X_L)$ for capacities

$\to X_{C}=\frac{1}{W L}$

for

$\to X_{L}=wL$

When $w \longrightarrow 2w$

$L\longrightarrow \frac{L}{2}$

then

$\to X_{L}=2 w \times \frac{L}{2}=wL$

therefore, $X_{L}$ remains at the same so, the maximum current remains the in same ckt.

4 0

2 years ago

child slides down a snow‑covered slope on a sled. At the top of the slope, her mother gives her a push to start her off with a s

Strike441 [17]

Answer:

θ = 13.7º

Explanation:

According to the work-energy theorem, the change in the kinetic energy of the combined mass of the child and the sled, is equal to the total work done on the object by external forces.
The external forces capable to do work on the combination of child +sled, are the friction force (opposing to the displacement), and the component of the weight parallel to the slide.
As this last work is just equal to the change in the gravitational potential energy (with opposite sign) , we can write the following equation:

$\Delta K + \Delta U = W_{nc} (1)$

ΔK, is the change in kinetic energy, as follows:

$\Delta K = \frac{1}{2}* m* (v_{f} ^{2} - v_{0} ^{2}) (2)$

ΔU, is the change in the gravitational potential energy.
If we choose as our zero reference level, the bottom of the slope, the change in gravitational potential energy will be as follows:

$\Delta U = 0 - m*g*h = -m*g*d* sin\theta (3)$

Finally, the work done for non-conservative forces, is the work done by the friction force, along the slope, as follows:

$W_{nc} = F_{f} * d * cos 180\º \\\\ = 0.2*m*g*d* cos 180\º = -0.2*m*g*d (4)$

Replacing (2), (3), and (4) in (1), simplifying common terms, and rearranging, we have:

$\frac{1}{2}* (v_{f} ^{2} - v_{0} ^{2}) = g*d* sin\theta -0.2*g*d$

Replacing by the givens and the knowns, we can solve for sin θ, as follows: $\frac{1}{2}*( (4.30 m/s) ^{2} - (0.75 m/s)^{2}) = 9.8 m/s2*25.5m* sin\theta -0.2*9.8m/s2*25.5m\\ \\ 8.56 (m/s)2 = 250(m/s)2* sin \theta -50 (m/s)2\\ \\ sin \theta = \frac{58.6 (m/s)2}{250 (m/s)2} = 0.236$ ⇒ θ = sin⁻¹ (0.236) = 13.7º

8 0

2 years ago

How to calculate the angle of a resultant<br>

stiv31 [10]

Answer:

The direction angle θ of the resultant in the Polar (positive) specification is then θ = α + 60°. The Law of Cosines is used to calculate the magnitude (r) and the Law of Sines is used to calculate the angle (α).

3 0

2 years ago

A toy car is moving along with 0. 50 joules of kinetic energy. If its speed is doubled, then its new kinetic energy is.

antoniya [11.8K]

Answer:

2 Joules

Explanation:

Kinetic Energy = 1/2 of (Mass x Velocity^2)

7 0

2 years ago

How are EM waves and Mechanical waves different? * Check all that apply 5 points EM waves can travel through a vacuum. All EM wa

Ludmilka [50]

Particles transfer energy physically from one to the other either horizontally in a longitudinal wave, vertically in a transverse wave, or in circles in a surface wave. Waves can also be electromagnetic, which are always transverse and do not require a medium to propagate, like light waves traveling through space.

6 0

2 years ago