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2 years ago

How can acceleration be described?

Physics

2 answers:

krek1111 [17]2 years ago

7 0

Answer:

The definition of acceleration is: Acceleration is a vector quantity that is defined as the rate at which an object changes its velocity. An object is accelerating if it is changing its velocity.

Explanation:

ivanzaharov [21]2 years ago

5 0

Answer:

A vehicle's capacity to gain speed within a short time.

Explanation:

Hope that helps you :)

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Under which conditions do both convex and concave mirrors form virtual images? State whether or not each can form a real image.

-Dominant- [34]

Hi!

Convex mirrors always form virtual images regardless of object position and the image is formed behind the mirror in both cases I.e. at infinity and between infinity and the pole. The image is diminished in both the cases.

Concave mirrors form a virtual image when the object is placed in between the Principal focus and the Pole and the image is formed behind the mirror. The virtual image is enlarged in this case. In all other object positions I.e. at infinity, beyond Center of curvature, at Center,between centre of curvature and principal focus and at principal focus, a real and an inverted image of the object is formed.
The ray diagrams for all the positions for the object in concave and convex mirrors are given below:

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2 years ago

Weight is the downward pull of<br> on mass. What one word completes the sentence?

lesantik [10]

The word "gravity" belongs between "of" and "on".

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2 years ago

A rocket is launched from Earth (mass ME, radius RE) with velocity v° and reaches radial distance r=6RE with velocity v°/10. Exp

Aliun [14]

The velocity, expressed in terms of ME, RE is given as $V_0 = \sqrt{98.99R_E}$ .

The maximum height that the rocket could reach if launched vertically is H = (¹/₂v₀²)/g.

<h3>Maximum height of the rocket</h3>

The maximum height reached by the rocket can be modeled using conservation of energy as shown below;

P.Ei + K.Ei = K.Ef + P.Ef

$M_EgR_E + \frac{1}{2} M_EV_0^2= \frac{1}{2} M_E(\frac{V_o}{10} )^2+ M_Eg(6R_E)\\\\\frac{1}{2} M_EV_0^2 - \frac{1}{2} M_E(\frac{V_o}{10} )^2 = M_Eg(6R_E) - M_EgR_E\\\\0.495M_EV_0^2= 5gM_ER_E\\\\0.495V_0^2= 5gR_E\\\\V_0 = \sqrt{\frac{5gR_E}{0.495} } \\\\V_0 = \sqrt{98.99R_E}$

<h3>Maximum height when it is launched vertically</h3>

P.E = K.E

mgH = ¹/₂mv²

H = (¹/₂v₀²)/g

Learn more about conservation of energy here: brainly.com/question/166559

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1 year ago

you walk from the park to your friend's house, then back to your house. (a) What is the distance traveled? (b) What is your disp

777dan777 [17]

Explanation:

The total distance in a path is called distance.

The shortest distance between two points is called displacement.

a) Here, the distance travelled between the park to your friend's house and back is

Distance between park to friends house + Distance from friend's house to your house.

b) Displacement would be the shortest distance between the park and your house.

a) Distance walked between your house to library and back is

Distance between your house and library + Distance between your house and library

b) Displacement would be zero (0) as the distance between you initial point and final point is zero. Here, the initial and final points are the same

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2 years ago

What is the most likely effect on the life of a plant if a student cuts it’s flowers?

goblinko [34]

Answer:

Explanation:

The reproduction parts of the plant are in the flower and around it so this would eliminate the plants ablity to reproduce.

5 0

2 years ago

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