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tatuchka [14]
3 years ago
5

The energy released in a nuclear reaction comes from

Chemistry
2 answers:
slavikrds [6]3 years ago
6 0

The energy is released from the "conserved" energy of an atom

riadik2000 [5.3K]3 years ago
6 0

it comes from some of the mass deteriorating into photons

You might be interested in
Please help me ಥ_ಥ
dexar [7]

Energy is stored in chemical bonds during photosynthesis.

During photosynthesis, the radiant energy from the sun is converted to chemical energy in carbohydrates.

Inorganic materials in the form of carbon dioxide and oxygen combine to form carbohydrates in the presence of radiant energy according to the equation below:

6CO_2 + 6H_2O ---> C_6H_1_2O_6 + 6O_2

The energy is thus, stored in chemical bonds in the carbohydrate and this is what is oxidized during respiration to release the locked energy.

More on photosynthesis can be found here: brainly.com/question/1388366

7 0
2 years ago
Read 2 more answers
Key words how atoms work?
pantera1 [17]
Most atoms have three different subatomic particles inside them: protons, neutrons, and electrons. The protons and neutrons are packed together into the center of the atom(which is called the nucleus) and the electrons, which are very much smaller, whizz around the outside. Most of an atom is empty space.

I hope this helps you! :D
3 0
3 years ago
What part of an Atom undergoes change during radioactive decay
Aloiza [94]
It is clear that the core is subject to change
7 0
3 years ago
Notice that "SO4" appears in two different places in this chemical equation. SO42− is a polyatomic ion called "sulfate." What nu
vichka [17]

Answer:

3.

Explanation:

Hello,

In this case, it is convenient to write the chemical reaction as:

CaSO_4+AlCl_3\rightarrow CaCl_2+Al_2(SO_4)_3

Which balanced turns out:

3CaSO_4+2AlCl_3\rightarrow 3CaCl_2+Al_2(SO_4)_3

Thus the number that should be in front of the calcium sulfate is 3 in order to balance the reaction.

Best regards.

8 0
3 years ago
Suppose the half-life is 9.0 s for a first order reaction and the reactant concentration is 0.0741 M 50.7 s after the reaction s
bazaltina [42]

<u>Answer:</u> The time taken by the reaction is 84.5 seconds

<u>Explanation:</u>

The equation used to calculate half life for first order kinetics:

k=\frac{0.693}{t_{1/2}}

where,

t_{1/2} = half-life of the reaction = 9.0 s

k = rate constant = ?

Putting values in above equation, we get:

k=\frac{0.693}{9}=0.077s^{-1}

Rate law expression for first order kinetics is given by the equation:

k=\frac{2.303}{t}\log\frac{[A_o]}{[A]}     ......(1)

where,

k = rate constant  = 0.077s^{-1}

t = time taken for decay process = 50.7 sec

[A_o] = initial amount of the reactant = ?

[A] = amount left after decay process =  0.0741 M

Putting values in equation 1, we get:

0.077=\frac{2.303}{50.7}\log\frac{[A_o]}{0.0741}

[A_o]=3.67M

Now, calculating the time taken by using equation 1:

[A]=0.0055M

k=0.077s^{-1}

[A_o]=3.67M

Putting values in equation 1, we get:

0.077=\frac{2.303}{t}\log\frac{3.67}{0.0055}\\\\t=84.5s

Hence, the time taken by the reaction is 84.5 seconds

6 0
3 years ago
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