The energy released in a nuclear reaction comes from
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We have to know final temperature of the gas after it has done 2.40 X 10³ Joule of work.
The final temperature is: 75.11 °C.
The work done at constant pressure, W=nR(T₂-T₁)
n= number of moles of gases=6 (Given), R=Molar gas constant, T₂= Final temperature in Kelvin, T₁= Initial temperature in Kelvin =27°C or 300 K (Given).
W=2.4 × 10³ Joule (Given)
From the expression,
(T₂-T₁)=
(T₂-T₁)=
(T₂-T₁)= 48.11
T₂=300+48.11=348.11 K= 75.11 °C
Final temperature is 75.11 °C.
Explanation:
The given data is as follows.
T = 298 K, = -5645 kJ/mol
= -5798 kJ/mol
Relation between and
are as follows.
=
-5798 kJ/mol = -5645 kJ/mol -
-153 kJ/mol = -
= 0.513 kJ/mol K
Now, temperature is = (37 + 273) K = 310 K
Since, =
=
= (-5645 kJ/mol - 159.03 kJ/mol)
= -5804.03 kJ/mol
As, change in Gibb's free energy = maximum non-expansion work
= -5804.03 kJ/mol - (-5798 kJ/mol)
= -6.03 kJ/mol
Therefore, we can conclude that the additional non-expansion work is -6.03 kJ/mol.