1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
irina1246 [14]
3 years ago
15

Una piedra es lanzada horizontalmente desde la azote de un edificio de 30 metros de altura, con una velocidad de 12 m/s. Hallar

el tiempo que la piedra cae al piso y a qué distancia de la base del edificio llego la piedra.
Chemistry
1 answer:
drek231 [11]3 years ago
3 0

Answer: La piedra tarda 2.47 segundos en caer al suelo, y cae a 29.64 metros de la base del edificio.

Explanation:

Ok, tenemos 2 sistemas de ecuaciones para este problema.

Primero, el vertical:

La aceleración es la aceleración gravitatoria, entonces:

a = -9.8m/s^2

para la velocidad podemos integrar sobre el tiempo y obtenemos

v = (-9.8m/s^2)*t + v0

donde v0 es la velocidad inicial, pero la velocidad inicial es solo horizontal, entonces v0 = 0.

Para la posición integramos de vuelta:

p = (1/2)*(-9.8m/s^2)*t^2 + p0

donde p0 es la posición inicial, en este caso, 30m

p = (-4.9m/s^2)*t^2 + 30m

la piedra va a llegar al piso cuando la posición vertical sea igual a 0m

p = 0m =  (-4.9m/s^2)*t^2 + 30m

de aca podemos despejar el tiempo que la piedra tarda en llegar al suelo.

t = √(30/4.9) segundos = 2.47 s.

Ahora, las ecuaciones para el movimiento horizontal son:

Aceleración nula, pues no hay ninguna fuerza actuando en la dirección horizontal.

a = 0

para la velocidad, integramos sobre el tiempo:

v = 0*t + v0 = v0

donde v0 es la velocidad inicial, en este caso, es 12m/s

v = 12m/s

para la posición integramos de vuelta:

p = 12m/s*t + p0

en este caso podemos asumir que estamos inicialmente en el punto x = x0, asi que la posición inicial es p0 = x0.

p = 12m/s*t + x0

entonces, si queremos calcular la distancia entre la base del edificio y el punto donde cae la piedra, tenemos que calcular:

D = p(2.47s) - p(0s)

D = 12m/s*2.47s + x0 - (12m/s*0s + x0)

D = 29.64m

La piedra tarda 2.47 segundos en caer al suelo, y cae a 29.64 metros de la base del edificio.

You might be interested in
How many liters of O2 are required to produce 3.99 miles of CO2?
Elena L [17]

Answer:

A fat choad

Explanation:

2+2=4

6 0
3 years ago
Prior to hosting an international soccer match, the local soccer club needs to replace the artifical turf on their field with gr
GuDViN [60]

Answer:

It will cost $68,620.5 to the club to add the grass turf to their field.

Explanation:

length of the field = l = 0.102 km = 0.102 × 1000 m

( 1km = 1000 m)

Width of the field w = 0.069 km = 0.069 × 1000 m

Area of the field , A= l × w

A=0.102\times 1000 m\times 0.069\times 1000 m=7,038 m^2

Cost of grass turfing = 9.75 \$/m^2

Cost of grass turfing on field of 7,038 m^2 :

=7,038 m^2\times 9.75 \$/m^2=\$68,620.5

It will cost $68,620.5 to the club to add the grass turf to their field.

4 0
3 years ago
Two elements that have properties similar to those of the element potassium(K). To those of krypton(Kr)
balu736 [363]

Answer:

Calcium (Ca) and Scandinavium (Sc)

Explanation:

They are all on the same period.

8 0
3 years ago
What is the effect on this???
Setler79 [48]
It being transmitted
7 0
3 years ago
How many grams of barium sulfate are produced if 25.34 mL of 0.113 M BaCl2 completely react given the reaction: BaCl2 (aq) + Na2
jeyben [28]

<u>Answer:</u> The amount of barium sulfate produced in the given reaction is 0.667 grams.

<u>Explanation:</u>

To calculate the number of moles from molarity, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}

Molarity of barium chloride = 0.113 M

Volume of barium chloride = 25.34 mL = 0.02534 L   (Conversion factor: 1 L = 1000 mL)

Putting values in above equation, we get:

0.113mol/L=\frac{\text{Moles of barium chloride}}{0.02534L}\\\\\text{Moles of barium chloride}=0.00286mol

For the given chemical reaction:

BaCl_2(aq.)+Na_2SO_4(aq.)\rightarrow BaSO_4(s)+2NaCl(aq.)

By Stoichiometry of the reaction:

1 mole of barium chloride is producing 1 mole of barium sulfate.

So, 0.00286 moles of barium chloride will produce = \frac{1}{1}\times 0.00286mol=0.00286mol of barium sulfate.

Now, to calculate the mass of barium sulfate, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Molar mass of barium sulfate = 233.38 g/mol

Moles of barium sulfate = 0.00286 moles

Putting values in above equation, we get:

0.00286mol=\frac{\text{Mass of barium sulfate}}{233.38g/mol}\\\\\text{Mass of barium sulfate}=0.667g

Hence, the amount of barium sulfate produced in the given reaction is 0.667 grams

4 0
3 years ago
Other questions:
  • What is essential to living things because many of the chemical reactions that occur in living things require it?
    6·2 answers
  • Which are examples of science rather than pseudoscience? Check all that apply. People can get rid of hiccups by holding their br
    11·1 answer
  • An ideal gas in a sealed container has an initial volume of 2.55 L. At constant pressure, it has cooled to 16.00 degrees Celcius
    8·1 answer
  • The layer of Earth that has the lightest elements?
    7·1 answer
  • (a) Coulomb's law describes the magnitude of the _____________ between two charged particles.
    13·1 answer
  • Plz help I’ll give brainliest!!!
    15·1 answer
  • A monatomic ion with a charge of 2 has an electronic configuration of 1s22s22p6. This ion is a(n) _______ . What is the chemical
    13·1 answer
  • List five compound in chemistry and their formula​
    10·1 answer
  • PLEASE HELP ME!!!!!!!!!
    12·1 answer
  • Analyze How would tides be affected if the<br> Moon was farther away from Earth?
    15·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!