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What is the total number of moles of aluminum oxide that can be formed when 54 grams of aluminum reacts completely with oxygen?

umka2103 [35]

4Al + 3O₂ → 2Al₂O₃

m(Al)=54 g
M(Al)=27 g/mol

n(Al₂O₃)=n(Al)/2

n(Al)=m(Al)/M(Al)

n(Al₂O₃)=m(Al)/{2M(Al)}

n(Al₂O₃)=54/{2*27}= 1 mol

3 0

3 years ago

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If 56.0 ml of bacl2 solution is needed to precipitate all the sulfate ion in a 758 mg sample of na2so4, what is the molarity of

Nady [450]

Answer is: molarity of solution is 0,0951 M.
Chemical reaction: BaCl₂ + Na₂SO₄ → BaSO₄ + 2NaCl.
m(Na₂SO₄) = 758 mg ÷ 1000 mg/g = 0,758 g.
n(Na₂SO₄) = m(Na₂SO₄) ÷ M(Na₂SO₄).
n(Na₂SO₄) = 0,758 g ÷ 142 g/mol.
n(Na₂SO₄) = 0,00533 mol.
From chemical reaction: n(Na₂SO₄) : n(BaCl₂) = 1 : 1.
n(BaCl₂) = 0,00533 mol.
V(BaCl₂) = 56,0 mL = 0,056 L.
c(BaCl₂) = n(BaCl₂) ÷ V(BaCl₂).
c(BaCl₂) = 0,00533 mol ÷ 0,056 L.
c(BaCl₂) = 0,0951 mol/L.

3 0

3 years ago

Predict the geometry around the central atom in SO2- A) trigonal pyramidal B) tetrahedral C) octahedral D) trigonal planar E) tr

liubo4ka [24]

<u>Answer:</u> The correct answer is Option D.

<u>Explanation:</u>

To calculate the hybridization of $SO_2$ , we use the equation:

$\text{Number of electron pair}=\frac{1}{2}[V+N-C+A]$

where,

V = number of valence electrons present in central atom (S) = 6

N = number of monovalent atoms bonded to central atom = 0

C = charge of cation = 0

A = charge of anion = 0

Putting values in above equation, we get:

$\text{Number of electron pair}=\frac{1}{2}[6]=3$

The number of electron pair around the central metal atom are 3. This means that the hybridization will be $sp^2$ and the electronic geometry of the molecule will be trigonal planar.