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FrozenT [24]
4 years ago
13

HOW CAN I SOLVE THIS QUESTION? PLEASE HELP The movement of a locomotive piston in the cylinder is limited to 0.76 m. Assume that

the piston makes a simple harmonic movement that makes 180 revolutions per minute, and find its maximum speed.
Physics
1 answer:
lions [1.4K]4 years ago
5 0

Answer:

7.2 m/s

Explanation:

The maximum speed is the amplitude times the frequency.

v = Aω

v = (0.76 m / 2) (180 rev × 2π rad/rev / 60 s)

v = 7.2 m/s

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When gasoline is burned in the cylinder of an engine, it creates a high pressure that pushes the piston. If the pressure is 100.
Marianna [84]

Answer:

\dot W=2.1074\ hp

Explanation:

Given:

  • pressure on the piston, P=100\ psi=689476\ Pa
  • diameter of the piston, d=3\ in=0.0762\ m
  • displacement of the piston, s=0.05\ m
  • time taken in the piston displacement, t=0.1\ s

<u>Now, we find the force on the piston:</u>

F=P.A

where, A = area upon which pressure acts

A=\pi.\frac{d^2}{4}

A=\pi.\frac{0.0762^2}{4}

A=0.00456\ m^2

\therefore F=689476\times 0.00456

F=3144.2638\ N

<u>we know that Power is given as:</u>

\dot W=\frac{F.s}{t}

\dot W=\frac{3144.2638\times 0.05}{0.1}

\dot W=1572.1319\ W

\dot W=2.1074\ hp

6 0
3 years ago
HELP ASAP PLEEEEES
matrenka [14]

Explanation:

33. The 1.5kg owl is now soaring at 20m/s. What is the owl’s KE?

a. Step 1: Formula <u>½mv²</u>

b. Step 2: Data m = <u>1</u><u>.</u><u>5</u><u> </u><u>kg</u>, v = <u>2</u><u>0</u><u> </u><u>m</u><u>/</u><u>s</u>

c. Step 3: Solve

KE = (1/2)(<u>1</u><u>.</u><u>5</u>)(<u>2</u><u>0</u>)² = <u>3</u><u>0</u><u>0</u><u> </u><u>J</u>

6 0
3 years ago
What causes scoliosis
klemol [59]

Answer:

<em>Scoliosis is a sideways curvature of the spine. Scoliosis is a sideways curvature of the spine that occurs most often during the growth spurt just before puberty. While scoliosis can be caused by conditions such as cerebral palsy and muscular dystrophy, the cause of most scoliosis is unknown.</em>

6 0
3 years ago
Read 2 more answers
In one cycle, a freezer uses 800 J of electrical energy in order to remove 1735 J of heat from its freezer compartment at 10.0°F
Lubov Fominskaja [6]

Answer:

Explanation:

A)

W = work done by the freezer = 800 J

Q = heat removed from the freezer = 1735 J

Q' = Heat expelled into the room

Coefficient of performance is given as

\beta = \frac{Q}{W}

inserting the values

\beta = \frac{1735}{800}

\beta = 2.2

B)

Heat expelled is given as

Q' = W + Q

Q' = 800 + 1735

Q' = 2535 J

8 0
3 years ago
A 2800 kg truck moving at 12 m/s to the right hits a stopped 1100 kg car. What is the combined velocity the moment they stick to
leva [86]

Answer:

The combined velocity is 8.61 m/s.

Explanation:

Given that,

The mass of a truck, m = 2800 kg

Initial speed of truck, u = 12 m/s

The mass of a car, m' = 1100 kg

Initial speed of the car, u' = 0

We need to find the combined velocity the moment they stick together. Let it is V. Using the conservation of momentum.

m_1v_1+m_2v_2=(m_1+m_2)V\\\\V=\dfrac{m_1v_1+m_2v_2}{(m_1+m_2)}\\\\V=\dfrac{2800\times 12+0}{2800+1100}\\\\V=8.61\ m/s

So, the combined velocity is 8.61 m/s.

5 0
3 years ago
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