The mass of a body if the acceleration the body used to move is given as 5 m/s-2 will be 3 kg.
<h3>What is force?</h3>
Force is defined as the push or pulls applied to the body. Sometimes it is used to change the shape, size, and direction of the body.
Force is defined as the product of mass and acceleration. Its unit is Newton.
Given data;
Force,F = 30 N
Mass,m = kg
Acceleration,a = 5 m/s²
The force is found as;
F=ma
30 N =m kg × 5 m/s²
m=3 kg
Hence the mass of a body will be 3 kg.
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Answer:
Option B. doubles
Explanation:
This can be explained by the definition of capacitance that charge on the capacitor will remain constant irrespective of the voltage applied.
This can be given as:
Q ∝ V or Q = CV
where,
Q = charge
V = Voltage
C = Capacitance
So, when V is doubled, C shoul reduce to half to main constant charge on the capacitor:
V' = 2V
C' = ![\frac{1}{2}C](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7DC)
Also , Energy stored in a capacitor, E is given by:
E =
(1)
Now, when
V' = 2V
C' = ![\frac{1}{2}C](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7DC)
Using eqn (1):
E' = ![\frac{1}{2}C'V'^{2}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7DC%27V%27%5E%7B2%7D)
Energy, E' =
E' =
= 2E
Answer:
v = 16.23 m/s²
Explanation:
In the problems that have friction force this must be included in the energy conservation equation, in these cases the friction force performs dissipative work that is equal to the decrease in mechanical energy
=
- ![E_{mo}](https://tex.z-dn.net/?f=E_%7Bmo%7D)
Let's look for the initial mechanical energy
= Ke = ½ k x²
Final energy
= K + U = ½ m v² + mg y
The work of the rubbing force is
= - fr d.
Let's look for the missing terms, let's start with the amount the spring compresses, let's use Hooke's law
F = - k x
x = F / k
x = 4400/1100
x = 4 m
Let's write the equation and calculate
-Fr d = (1/2 m v² + ½ mg y) - ½ k x²
½ m v² = -fr .d + 1 / 2k x² - ½ m g y
v² = 2/m (- fr .d + 1/2 k x² - ½ m g y)
v² = 2/60 (-40 4 + ½ 1100 4² - ½ 60 9.8 2.5)
v = √(7905/ 30)
v = 16.23 m/s²
Answer:
C. 8I.
Explanation:
As moment of inertia for a bar is proportional to the product of its mass and the square of its length, doubling the mass will double the moment of inertia. Doubling the length will quadruple the moment of inertia. Doing both will make the moment of inertia 2(4) = 8 times larger
Electrons are the right subatomic particle