Answer:
a
Explanation:
how well a material shines or reflects light
Explanation:
For this problem, use the first law of thermodynamics. The change in energy equals the increase in heat energy minus the work done.
ΔU=Q−W
We are not given a value for work, but we can solve for it using the force and distance. Work is the product of force and displacement.
W=FΔx
W=3N×2m
W=6J
Now that we have the value of work done and the value for heat added, we can solve for the total change in energy.
ΔU=Q−W
ΔU=10J−6J
ΔU=4J
Answer is 4J
i think this may help you very much
Answer:
a) P1=100kpa
V1=6m³
V2=?
P2=50kpa
rearranging mathematically the expression for Boyle's law
V2=(P1V1)/P2=(100×6)/50=12m³
b) same apartment as in (a) but only the value of P2 changes
=> V2=(100×6)/40=15m³
Explanation:
since temperature is not changing we use Boyle's law. mathematically expressed as P1V1=P2V2
