Answer:
ATMOSPHERIC PRESSURE HAS IMPORTANT EFFECTS ON WATER CHEMISTRY AND WEATHER CONDITION . IT AFFECTS THE AMOUNT OF GAS THAT CAN DISSOLVE IN WATER. LIKE OXYGEN CAN DISSOLVE IN HIGH PRESSURE MORE THAN LOWER AIR PRESSURE.
Answer:
779.87 N/m²
Explanation:
Pressure = Force (F) / Area (A)
Recall :
Force = ma ; mass * acceleration due to gravity
a = 9.8 m/s² ; mass = 0.4kg
Force, F = 0.4 * 9.8 = 3.92 N
Area = πr² ; r = Radius = 4cm = 4 / 100 = 0.04 m
Area = π0.04² = 0.0050265 m²
Hence,
Pressure = 3.92 / 0.0050265
Pressure = 779.86670 N/m²
Pressure = 779.87 N/m²
Answer:
1.65 atm
Explanation:
Applying,
PV = nRT....................... Equation 1
Where P = Pressure, V = Volume, n = number of moles, R = malar gas constant, T = Temperature.
Make P the subject of the equation
P = nRT/V..................... Equation 2
From the question,
Given: n = 3.27 moles, V = 50.0 L, T = 35 °C = (273+35) = 308K
Constant: R = 0.082L.atm/K.mol
Substitute these values into equation 2
P = 3.27(0.082)(308)/(50)
P = 1.65 atm
Avogadros number is the definition of a mole. SO a mole is 1 avogadros number of atoms. molar mass is how much 1 avogadros number of atoms weighs. each element on the periodic table has a different mass, so 1 mole of each of the elements has a different molar mass.
Refer to the diagram shown below.
Let m = the mass (g) of the door.
Let v = the launch velocity
Let u = the velocity of the door after impact.
Elastic impact (rubber ball):
The rubber ball bounces off the door with presumably elastic impact, which means that both momentum and kinetic energy are conserved.
Conservation of momentum requires that
400v = -400v + mu
Therefore

Inelastic impact (clay):
The clay sticks to the door after impact.
Conservation of momentum requires that
400g = (m+400)u
Therefore

When we compare magnitudes of u for the door, we find that

Clearly, the elastic impact creates a greater value of u for the door.
Answer:
The rubber ball creates a larger impulse to the door because the nature of its impact is approximately elastic.