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ehidna [41]
3 years ago
7

What are the advantages of atmospheric pressure?​

Physics
2 answers:
Harrizon [31]3 years ago
8 0

Answer:

ATMOSPHERIC PRESSURE HAS IMPORTANT EFFECTS ON WATER CHEMISTRY AND WEATHER CONDITION . IT AFFECTS THE AMOUNT OF GAS THAT CAN DISSOLVE IN WATER. LIKE OXYGEN CAN DISSOLVE IN HIGH PRESSURE MORE THAN LOWER AIR PRESSURE.

Andrew [12]3 years ago
4 0

Answer:

it effects the amount of gas that dissolve in water

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What is the control group
otez555 [7]

A control group in a scientific experiment is a group separated from the rest of the experiment, where the independent variable being tested cannot influence the results. This isolates the independent variable 's effects on the experiment and can help rule out alternative explanations of the experimental results.

8 0
3 years ago
Read 2 more answers
200 J of work is done when a force is applied to an object and the object moves 10 m to the right. How much Force was applied?
ArbitrLikvidat [17]

Answer:

 20N

Explanation:

Given parameters:

Work done  = 200J

Distance moved  = 10m

Unknown:

Amount of force applied  =?

Solution:

Work done is the force applied on a body to move it in the direction of the force.

      Work done  = force x distance

The unit of work done is in joules

Since the unknown is force, we make it the subject of the expression;

           Force  = \frac{Work done}{distance}

           Force  = \frac{200}{10}   =  20N

5 0
4 years ago
If a wave's third harmonic has a frequency of 24 Hz, what is its
Charra [1.4K]

Answer:

8 Hz, 48 Hz

Explanation:

The standing waves on a string (or inside a pipe, for instance) have different modes of vibrations, depending on how many segments of the string are vibrating.

The fundamental frequency of a standing wave is the frequency of the fundamental mode of vibration; then, the higher modes of vibration are called harmonics. The frequency of the n-th harmonic is given by

f_n = nf_1

where

f_1 is the fundamental frequency

In this problem, we know that the wave's third harmonic has a frequency of

f_3=24 Hz

This means this is the frequency for n = 3. Therefore, we can find the fundamental frequency as:

f_1=\frac{f_3}{3}=\frac{24}{3}=8 Hz

Now we can also find the frequency of the 6-th harmonic using n = 6:

f_6 = 6 f_1 = 6 (8)=48 Hz

6 0
3 years ago
A forest is most sustainable when it has-
ollegr [7]
I think it is D
Hope my answer help you?
5 0
3 years ago
A low orbit satellite at 100 km altitude had a camera that resolved a car location to within 0.3 meter. Find the minimum diamete
NeX [460]

Answer:

Minimum diameter of the camera lens is 22.4 cm

The focal length of the camera's lens is 300cm

Explanation:

y = Resolve distance = 0.3 m

h = Height of satellite = 100 km

λ = Wavelength = 550 nm

Angular resolution

tan\theta\approx \theta =\frac{y}{h}\\\Rightarrow \theta=\frac{0.3}{100\times 10^3}=3\times 10^{-6}

From Rayleigh criteria

sin\theta=1.22\frac{\lambda}{D}\\\Rightarrow D=1.22\frac{\lambda}{sin\theta}\\\Rightarrow D=1.22\frac{550\times 10^{-9}}{sin3\times 10^{-6}}=0.2236\ m=22.4\ cm

Minimum diameter of the camera lens is 22.4 cm

Relation between resolvable feature, focal length and angular resolution

d=f\Delta \theta\\\Rightarrow f=\frac{d}{\Delta \theta}\\\Rightarrow f=\frac{9\times 10^{-6}}{3\times 10^{-6}}=3\ m=300\ cm

The focal length of the camera's lens is 300cm

3 0
3 years ago
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