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Nuetrik [128]
2 years ago
5

If the concentration of mercury in the water of a polluted lake is 0.250 μg (micrograms) per liter of water, what is the total m

ass of mercury in the lake, in kilograms, if the lake has a surface area of 18.5 square miles and an average depth of 39.0 feet?
Chemistry
1 answer:
aleksandr82 [10.1K]2 years ago
8 0

Answer:

142.36 kg

Explanation:

volume of water in the lake = surface area x depth

= 18.5 x ( 1760 x 3 )² x 39 ft³

= 2.011 x 10¹⁰ ft³

= 2.011 x 10¹⁰ x 28.3168 liter .

= 56.945 x 10¹⁰ liter .

concentration of mercury = .25 x 10⁻⁶ g / liter

= 25 x 10⁻⁸ g / liter

= 25 x 10⁻¹¹ kg / liter

mass of mercury in the water of lake

= 25 x 10⁻¹¹ x 56.945 x 10¹⁰ kg

= 142.36 kg .

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Answer:

The correct answer is B. It is spontaneous only at low temperatures.

Explanation:

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The spontaneity of a reaction is given by the equation:

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What is the standard unit used to measure mass
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3 years ago
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22. A piece of wood board contains approximately 6.76 X 1023 molecules of wood, C2H4920, how
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<h2>1.23 moles</h2>

Explanation:

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From the question we have

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We have the final answer as

<h3>1.23 moles</h3>

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