Here we have to get the effect of addition of 0.25 moles of gas C on the mole fraction of gas A in a mixture of gas having constant pressure.
On addition of 0.25 moles of C gas, the mole fraction of gas A will be
.
The partial pressure of gas A can be written as
=
×P (where
is the mole fraction of gas A present in the mixture and P is the total pressure of the mixture.
The mole fraction of gas A in a mixture of gas A and C is =
and
respectively.
Thus on addition of 0.25 moles of C gas, the mole fraction of gas A will be
.
Which is different from the initial state.
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Explanation:
Answer:
B
Explanation:
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Molar mass HCl :
HCl =1.01 + 35.45 => 36.46 g/mol
Number of moles ( solute) :
n = m / mm
n = 9.63 / 36.46
n = 0.2641 moles
Therefore :
M = moles / volume ( L )
M = 0.2641 / 1.5
=> 0.176 M