Answer:
BZ = 64/23 = 2 18/23
Step-by-step explanation:
The angle bisectors divide the triangle into proportional parts, so we have ...
CB/CY = AB/AY
CB = CY(AB/AY) = 4(8/6) = 16/3 . . . . multiply by CY and evaluate
and ...
BZ/CB = AZ/AC
BZ = AZ(CB/AC) . . . . multiply by CB
But we have ...
AZ = 8 -BZ, so this becomes ...
BZ = (8 -BZ)(16/3)/(10)
BZ(1 +8/15) = 64/15 . . . . add the BZ term on the right to both sides
BZ = (64/15)(15/23) = 64/23 . . . . divide by the coefficient of BZ
BZ = 64/23 = 2 18/23
The equation is 4 + 2n= -10
Answer:
B
as [tex]\cos(\theta)=\srqt{1-\sin^2(\theta)}\[tex]
and since theta is in second quadrant, where cosine is negative,
so -√(1-z²)
Answer: -7y+3
Step by step in picture below
Volume of cuboid =l×b×h
area of base of the cuboid =l×b
hence
volume of cuboid is = area of base × height
140=88×h
h=140÷88
h=5
