I think it’s going to be B.
Answer:
t≈8.0927
Step-by-step explanation:
h(t) = -16t^2 + 128t +12
We want to find when h(t) is zero ( or when it hits the ground)
0 = -16t^2 + 128t +12
Completing the square
Subtract 12 from each side
-12 = -16t^2 + 128t
Divide each side by -16
-12/-16 = -16/-16t^2 + 128/-16t
3/4 = t^2 -8t
Take the coefficient of t and divide it by 8
-8/2 = -4
Then square it
(-4) ^2 = 16
Add 16 to each side
16+3/4 = t^2 -8t+16
64/4 + 3/4= (t-4)^2
67/4 = (t-4)^2
Take the square root of each side
±sqrt(67/4) =sqrt( (t-4)^2)
±1/2sqrt(67) = (t-4)
Add 4 to each side
4 ±1/2sqrt(67) = t
The approximate values for t are
t≈-0.092676
t≈8.0927
The first is before the rocket is launched so the only valid answer is the second one
Answer:
The answer is C.
Step-by-step explanation:
Hit 'em with the Law of Sines.
sin(A)/a = sin(B)/b.
Let's say x is equal to "A", thus 5 is "a".
sin(x)/5 = sin(B)/b.
We could go for the obvious choice for "B", which would be the 90 degrees shown. To solve for the hypotenuse which will be "b", let's use the Pythagorean Theorem:
a^2 + b^2 = c^2
5^2 + 20^2 = c^2
25 + 400 = 425
sqrt(425) = about 20.6, which we can now substitute "b" with.
sin(x)/5 = sin(90)/20.6
sin(x)/5 = 1/20.6
sin(x)/5 = 0.04854...
sin(x) = 0.2427...
You can plug in sin^-1(0.2427) into your calculator, and you should end up with something like 14.047... which equates to answer choice C.
This is the correct answer try it....
133/8
Answer:
131
Step-by-step explanation:
