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Reil [10]
3 years ago
7

Carlos started at sea level, climbed a cliff to a height of 14 m, then dived 19 m. Find the level at which his dive ended.

Mathematics
1 answer:
Sidana [21]3 years ago
6 0

He started at 0, then he went up to a elevation of 14 m, then went down to 19m so it is 14-19 which =


-5 meters

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kirill115 [55]
If you're trying to solve for y, 
5y-4=7
bring over the -4
5y=11
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8 0
3 years ago
PLEASE HELP I GIVE BRAINLIEST
Galina-37 [17]
I Think it would either be D or C

(I’m not sure, let me know if I’m wrong)
4 0
3 years ago
Which of the following subsets of ℝ3×3 are subspaces of ℝ3×3? A. The 3×3 matrices whose entries are all greater than or equal to
Debora [2.8K]

Answer:

A. It is NOT a subspace of R^3x3

B. It IS a subspace of R^3x3

C. It IS a subspace of R^3x3

D. It is NOT a subspace of R^3x3

E  It is NOT a subspace of R^3x3

F.  It IS a subspace of R^3x3

Step-by-step explanation:

A way to show that a set is not a subspace, it´s enough to show that some properties of the definition of a vector spaces does not apply in that set or that operations under that set are not closed (we can get out of the set with linear combinations of elements in the set).

A. For definition of subspace, we know that every element has to have an additive inverse, but in set "A" (The 3×3 matrices whose entries are all greater than or equal to 0 ) every entry is greater than or equal to zero. In this set, there´s no additive inverse with the usual sum in R^3x3.

If sufficient to prove a set is a subspace showing that zero is in the set, there are additive inverses and that operations (sum and scalar multiplication) are closed in that set.

B.  Notice that the matrix 0 is in "B" (The 3×3 matrices A such that the vector (276) is in the kernel of A), also notice if A(276)=0 then -A(276)=0 so every additive inverse (of an element in "B") belongs to "B".

Now we just have to prove that operations are closed in "B". Let X,Y matrices in set "B" and let z a scalar from the field. We are going to show that:

zX+Y ∈ B

For definition of set B:

X(276)=0 and Y(276)=0

So for zX+Y:

(zX+Y)(276)=zX(276)+Y(276)=z(0)+(0)

(zX+Y)(276)=0

So (276) is in the kernel of zX+Y, i.e (zX+Y) ∈ B.

We conclude "B" (with usual sum and scalar product of matrices) is a subspace of R^3x3

C. Notice the matrix 0 ∈ "C" (The diagonal 3×3 matrices) and there are all the additive inverse of the elements in "C". With the usual sum and scalar product, if the only zero entries are above and under the diagonal, it´ll stay like that no matter what linear combination we do because sum of matrices is entry by entry, and for every entry above or under the diagonal the sum and scalar product of two elements is going to be 0 in the same entries under and above the diagonal. "C" is a subspace

D.  In set "D" (The non-invertible 3×3 matrices) it´s necessary to show that the sum is not closed:

Consider the following matrices and their sum:

X=\left[\begin{array}{ccc}1&0&0\\0&1&0\\0&0&0\end{array}\right]\\ Y=\left[\begin{array}{ccc}0&0&0\\0&0&0\\0&0&1\end{array}\right]

X+Y=I

We showed that sum is not closed in "C", so "C" is not a subspace of R^3x3

E. The definition of a reduced row-echelon matrix requires that the first element of a row must be 1, but with sum and scalar multiplication is easy to show that these pivot could easily change its value. So the set "E" is not closed under the usual operations under R^3x3.

F. The argument is similar to part C. No matter what linear combination we do, the last row is always going to be zero (with the usual operations in R^3x3). 0 ∈ "F" (The 3×3 matrices with all zeros in the third row) and all additive inverses (for an element in "F") is in "F", we affirm that "F" is a subspace of R^3x3

5 0
2 years ago
A middle school is selling tickets to a play. The number of child tickets sold is half the number of adult tickets sold. They so
Sidana [21]

Answer:

child tickets - 47

adult tickets - 94

Explanation:

since the number of adult tickets sold is twice that of the number of child tickets sold, we can divide 141 into three parts to find the number of child tickets sold.

141 ÷ 3 = <u>47</u> (number of child tickets sold)

we can now multiply this by two to find the number of adult tickets sold.

47 × 2 = <u>94</u>

i hope this helps! :D

8 0
3 years ago
1000^m / 100^n can be written in the form of 10^z express z in terms of m and n
Julli [10]

Answer:

z = 3m - 2n

Step-by-step explanation:

\frac{ {1000}^{m} }{ {100}^{n} }  =  {10}^{z}  \\  \\  \frac{ {10}^{3m} }{ {10}^{2n} }  =  {10}^{z}   \\  \\  {10}^{3m - 2n} =  {10}^{z}  \\  \\ 3m - 2n = z \\  \\  \huge \red{ \boxed{z = 3m - 2n}}

5 0
3 years ago
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