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4 years ago

PLEASE HELP ASAP!!!!!!!!!

Mathematics

1 answer:

Anna [14]4 years ago

8 0

First off to figure this out make the percent a decimal to do so move the . over to the left twice

.25

Now divide 225 by .25

which is equal to 900

Now divide 900 by 10

resulting in the answer

Kaitlin needs to work 90 hours to make $225 after deductions

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Please help me right away with these problems.

viktelen [127]

Q.34

$\sum\limits_{k=1}^{\infty}420\left(1.002\right)^{k-1}$

The infinite geometric series is converges if |r| < 1.

We have r =1.002 > 1, therefore our infinite geometric series is Diverges

Answer: c. Diverges, sum not exist.

Q.35

$\sum\limits_{k=1}^{\infty}-5\left(\dfrac{4}{5}\right)^{k-1}$

The infinite geometric series is converges if |r| < 1.

We have r = 4/5 < 1, therefore our infinite geometric series is converges.

The sum S of an infinite geometric series with |r| < 1 is given by the formula :

$S=\dfrac{a_1}{1-r}$

We have:

$a_1=-5\left(\dfrac{4}{5}\right)^{1-1}=-5\left(\dfrac{4}{5}\right)^0=-5\\\\r=\dfrac{4}{5}$

substitute:

$S=\dfrac{-5}{1-\frac{4}{5}}=-\dfrac{5}{\frac{1}{5}}=-5\cdot\dfrac{5}{1}=-25$

Answer: c. Converges, -25.

4 0

3 years ago

A moving trailer with a speed of 70km/h slows down its speed by 15% within 30 seconds. calculate the declaration of the trailer.

antoniya [11.8K]

Answer:

declaration = - 0.55 m/s²

Step-by-step explanation:

The declaration is a negative accelaration.

Therefore:

$a = \frac{v-u}{t}$

a = ?

v = 70 of 15% = 10.5 km/h to m/s = 2.9 m/s

u = 70 km/h to m/s = 19.4 m/s

t = 30 seconds

$a = \frac{2.9-19.4}{30}\\$

a = - 0.55 m/s²

7 0

3 years ago

What is the measure of EFC

Nesterboy [21]

Answer:

x=15 degrees

Step-by-step explanation:

angle EFC+angle ACF=180(allied angles)

5x + 7x =180

12x =180

x=15 degrees

Hope you got it

If you have any question just ask me

If you think this is the best answer please mark me as BRAINLIEST

7 0

3 years ago

What is the limit as x is approaching 0 of the absolute value of x

vesna_86 [32]

Recall that, an absolute value expression is a piece-wise in effect, thus we'd check the single-sided limits,

$\bf \lim\limits_{x\to 0}~|x|\implies 
\begin{cases}
\lim\limits_{x\to 0^-}~-x\\\\
\lim\limits_{x\to 0^+}~+x
\end{cases}\implies 
\begin{cases}
0\\\\
0
\end{cases}\implies \lim\limits_{x\to 0}~|x|=0$

6 0

4 years ago

Last one (for now)

Tasya [4]

Answer: A

Hope this helps :)

5 0

3 years ago