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3 years ago

Write an algebraic expression for the following word phrase: the quotient of r and 12?

Mathematics

2 answers:

Kobotan [32]3 years ago

7 0

Quotient= division so 12/r would be your answer

andre [41]3 years ago

4 0

The expression is r/12.

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HEY!! I’M REALLY DESPERATE RN FOR AN ANSWER SO LIKE HERE’S ALL MY POINTS!! Please show the work!

BabaBlast [244]

Answer:

see explanation

Step-by-step explanation:

One way to divide is to use the divisor as a factor in the numerator

Consider the numerator

x²(x - 3) + 3x² - x + 6

= x²(x - 3) + 3x(x - 3) + 9x - x + 6

= x²(x - 3) + 3x(x - 3) + 8(x - 3) + 24 + 6

= x²(x - 3) + 3x(x - 3) + 8(x - 3) + 30

quotient = x² + 3x + 8 , remainder = 30

$\frac{x^3-x+6}{x-3}$ = x² + 3x + 8 + $\frac{30}{x-3}$

6 0

3 years ago

Read 2 more answers

On a coordinate plane, triangle A B C is shown. Point A is at (0, 0), point B is at (3, 4), and point C is at (3, 2). What is th

Elena L [17]

Answer:

The area of triangle for the given coordinates is 1.5 $\sqrt{4.6}$

Step-by-step explanation:

Given coordinates of triangles as

A = (0,0)

B = (3,4)

C = (3,2)

So, The measure of length AB = a = $\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}$

Or, a = $\sqrt{(3-0)^{2}+(4-0)^{2}}$

Or, a = $\sqrt{9+16}$

Or, a = $\sqrt{25}$

∴ a = 5 unit

Similarly

The measure of length BC = b = $\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}$

Or, b = $\sqrt{(3-3)^{2}+(2-4)^{2}}$

Or, a = $\sqrt{0+4}$

Or, b = $\sqrt{4}$

∴ b = 2 unit

And

So, The measure of length CA = c = $\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}$

Or, c = $\sqrt{(3-0)^{2}+(2-0)^{2}}$

Or, c = $\sqrt{9+4}$

Or, c = $\sqrt{13}$

∴ c = $\sqrt{13}$ unit

Now, area of Triangle written as , from Heron's formula

A = $\sqrt{s\times (s-a)\times (s-b)\times (s-c)}$

and s = $\frac{a+b+c}{2}$

I.e s = $\frac{5+2+\sqrt{13}}{2}$

Or. s = $\frac{7+\sqrt{13}}{2}$

So, A = $\sqrt{(\frac{(7+\sqrt{13})}{2})\times ((\frac{(7+\sqrt{13})}{2})-5)\times (\frac{7+\sqrt{13}}{2}-2)\times (\frac{7+\sqrt{13}}{2}-\sqrt{13})}$

Or, A = $\sqrt{(\frac{(7+\sqrt{13})}{2})\times (\frac{(\sqrt{13}-3)}{2})\times (\frac{4+\sqrt{13}}{2})\times (\frac{7-\sqrt{13}}{2})}$

Or, A = $\frac{3}{2}$ × $\sqrt{1+\sqrt{13} }$

∴ Area of triangle = 1.5 $\sqrt{4.6}$

Hence The area of triangle for the given coordinates is 1.5 $\sqrt{4.6}$ Answer

7 0

3 years ago

Read 2 more answers

Find the interest rate

sp2606 [1]

the simple interest rate would be...colected by the end of the 5 years and the compounded is 2%

4 0

3 years ago

The reciprocal of 16 in a fraction

Varvara68 [4.7K]

Answer:

The reciprocal of 16 is 1/16

Step-by-step explanation:

The reasoning for this is that the reciprocal of any number is the opposite of it.

Another example would be: The reciprocal of 1/2 would be 2/1

5 0

3 years ago

Which statement is true.

belka [17]

All parallelograms are quadrilaterals.

5 0

2 years ago