Answer:
a). Mileage for carA= 
, and mileage for carB=
b).total mileage for both is similar to average of them= 
=![\frac{5x+4}{2x(x+1)}[tex]mil/gal](https://tex.z-dn.net/?f=%5Cfrac%7B5x%2B4%7D%7B2x%28x%2B1%29%7D%5Btex%5Dmil%2Fgal)
Step-by-step explanation:
It is given that the distance traveled by car 
And distance traveled by car 
We know the mileage is mile/gallon,
a).So mileage of car 
Similarly , the mileage for car 
b).total mileage for both is similar to average of them=
Now divide by 2 for total(average) mileage.
.
Thus those are the answers.
this pic is of empty set I guess bro
1/2 + 3/4 + 7/8
4/4(1/2)+ 2/2(3/4) + 7/8
4/8 + 6/8 + 7/8
4+ 6 + 7
—————
8
17 1
——. Or 2—-
8 8
He prepared 2 1/8 lbs of trail mix
We either need to see a picture of this and/or get more information about the measurements of the triangle. In general, the area outside of the triangle will be the area of the semi-circle minus the area of the triangle itself, or: 1/2*49*3.14 - 1/2 b*h of the triangle. That first part, which is the area of the semi-circle, works out to 76.93 So based on the info we have, it becomes 76.93 - 1/2*b*h of the triangle = area outside of triangle.
Answer:
f(x) = -3(x+3)(x-1)
Step-by-step explanation:
x = -3 & 1; f(x) = 9
f(x) = a(x-r1)(x-r2)
f(0) = a(x-r1)(x-r2) = 9; 9 = a(0-(-3))(0-1)
9 = a(3)(-1); 9 = a(-3)
a = -3
f(x) = -3(x+3)(x-1)
