Pyramid A has a height of 10 feet and a volume of 120 cubic feet. The base of Pyramid B has the same dimensions as Pyramid A but
is twice as tall. How is the volume affected by the change in the dimensions? (PLEASE HELP!)
2 answers:
A volume of a pyramid=base area×height/3
both the bases have same dimensions
pyramid B is twice the height of A
therefore the volume is doubled
Answer:
Pyramid B = 240 cubic feet, the volume doubled
Step-by-step explanation:
Pyramid A: 120/10 =12, 12 x 3 = 36 ft² base
Pyramid B: 36 ft² base x 20 ft tall x 1/3 = 240 cubic feet
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40/100 + 50/100 = 90/100
il lui reste 10/100 ou 21 $
10 % = 21 $
100 % = 210 $
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V=LWH
L=8
W=7
H=5
V=8*7*5=280 in^3
you need 280 in^3 of water
