Question

Assignment 10 Coulombic Equation Practice Directions: Complete the following problems to calculate the electrostatic force that is present in each situation. You will need to be sure to correctly substitute each of the variables in the equation. Once again the Equation is; F=K[(q1*q2)/r2]. Also Coulomb’s Constant is 8.98*109. What is the magnitude of the force a 1.5 x 106C charge exerts on a 3.2 x 104C charge located 1.5 m away?

Answer 1

Answer:

Magnitude of the force between the charges is F = 1.92×10^20N

Explanation:

Given the magnitude of force according to coulombs law

F =K[(q1*q2)/r2]

Where q1 and q2 are the charges

r is the distance between the charges

K is the coulombs constant

Substituting the given values, we have;

F = 8.98×10^9 × 1.5×10^6 × 3.2×10^4/1.5²

F = 43.1×10^19/2.25

F = 19.16×10^19N

F = 1.92×10^20N