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3 years ago

7

Volume or intensity of a sound wave is measured by the size of the _________ and reported in decibels. A) amplitude B) frequency

C) trough D) wavelength

2 answers:

Tasya [4]3 years ago

7 0

A.) amplitude (amplitude equates to the volume of a sound wave, frequency equates to the note that is played)

kotegsom [21]3 years ago

4 0

Volume or intensity of a sound wave is measured by the size of the amplitude. The greater the amplitude, the louder the sound.

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A 49 kg bear slides, from rest, 11 m down a lodgepole pine tree, moving with a speed of 3.3 m/s just before hitting the ground.

hichkok12 [17]

Answer:

a) $\Delta U_g=-5.3kJ$

b) $K=0.27kJ$

c) $F_f=0.45kN$

Explanation:

the gravitational potential energy is given by:

$U_g=m.g.h\\$

$\Delta U_g=m.g.h_f-m.g.h_i\\\Delta U_g=49kg*9.8m/s^2*(0m-11m)\\\Delta U_g=-5.3kJ$

The kinetic energy is given by:

$K=\frac{1}{2}m.v^2\\$

the initial kinetic energy is zero because the motion started from rest, so:

$K=\frac{1}{2}*49kg*(3.3m/s^2)^2\\K=0.27kJ$

applying the conservation of energy theorem:

$U_g-W_f=K_f\\W_f=-(\Delta K+\Delta U)\\W_F=5.3kJ-0.27kJ\\W_F=-5.0kJ$

The work done by the friction force is given by:

$W_f=F_f.h.cos(\theta)\\$

the angle of the force is 180 degrees because it's against the movement:

$F_f=\frac{W_f}{h.cos(\theta)}\\\\F_f=\frac{-5.0kJ}{11m.cos(180^o)}\\\\F_f=0.45kN$

8 0

3 years ago

Rocks formed from broken pieces of other rocks is classified as

chubhunter [2.5K]

C .Clastic,why you see (clastic called Detrial ,made of broken rocks so the answer is C

3 0

3 years ago

The temperature in Edinburgh falls by 2°C.<br><br>c) What is the new temperature in Edinburgh?

Gnoma [55]

Answer:

E-2 E is Edinburgh

Explanation:

3 0

3 years ago

A 2.0 kg otter starts from rest at the top of a muddy incline 85 cm long and slides down to the bottom in 0.50 s. What net force

Julli [10]

Answer:

The net force acting on the otter along the incline is 13.96 N.

Explanation:

It is given that,

Mass of the otter, m = 2 kg

Distance covered by otter, d = 85 cm = 0.85 m

It takes 0.5 seconds.

We need to find the net force acts on the otter along the incline. If a is the acceleration of the otter. It can be calculated using second equation of motion as :

$d=ut+\dfrac{1}{2}at^2$

Here, u = 0 (at rest)

$d=\dfrac{1}{2}at^2$

$a=\dfrac{2d}{t^2}$

$a=\dfrac{2\times 0.85}{0.5^2}$

$a=6.8\ m/s^2$

The net force acting on the otter along the incline is given by :

F = ma

$F=2\ kg\times 6.8\ m/s^2$

F = 13.6 N

So, the net force acting on the otter along the incline is 13.96 N. Hence, this is the required solution.

5 0

3 years ago

Calculate the wavelength of an electron mass 9.1*10^-31kg moving with a velocity of 2.0*10^6m/s (h=6.63*10^-34Js) (Hint: De Brog

Inga [223]

Answer:

Wavelength, $\lambda=3.64\times 10^{-10}\ m$

Explanation:

We have,

Velocity an electron is $2\times 10^6\ m/s$

Mass of an electron is $9.1\times 10^{-31}\ kg$

It is required to find the wavelength of electron. The De-Broglie wavelength of an electron is given by :

$\lambda=\dfrac{h}{mv}$

h is Planck's constant

$\lambda=\dfrac{6.63\times 10^{-34}}{9.1\times 10^{-31}\times 2\times 10^6}\\\\\lambda=3.64\times 10^{-10}\ m$

So, the wavelength of an electron is $3.64\times 10^{-10}\ m$ .

8 0

3 years ago